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prohojiy [21]
3 years ago
5

Please help me on this​

Mathematics
2 answers:
USPshnik [31]3 years ago
7 0
The answer for your question is -6/5
alexdok [17]3 years ago
5 0

Answer:

-6|5

Can I maybe be Brainliest

have a nice day Best regards

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Can someone help please?
Mariulka [41]

Answer:

Part 1) The area of the structure is 2,453.25\ ft^{2}

Part 2) The slab will contain  1,226.625\ ft^{3} of cement

Step-by-step explanation:

Part 1) Find the area of the structure

we know that

The area of the structure is equal to the area of rectangle plus the area of semicircle

<u><em>Find the area of rectangle</em></u>

The area of rectangle is equal to

A=LW

we have

L=70\ ft

W=30\ ft

substitute

A=(70)(30)

A=2,100\ ft^{2}

<u><em>Find the area of semicircle</em></u>

The area of semicircle is

A=\frac{1}{2}\pi r^{2}

we have

\pi =3.14

r=15\ ft

substitute

A=\frac{1}{2}(3.14)(15)^{2}

A=353.25\ ft^{2}

<u><em>Find the area of the structure</em></u>

Adds the areas

A=2,100+353.25=2,453.25\ ft^{2}

Part 2) If the structure is 6 in thick, how many cubic feet of cement will the slab contain?

Remember that

1\ foot=12\ inches

Convert inches to feet

6\ in=6/12=0.5\ ft

<u><em>Find the volume of the structure</em></u>

To obtain the volume , multiply the area by 0.5 ft (thick)

so

V=2,453.25*0.5=1,226.625\ ft^{3}

7 0
3 years ago
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