If length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5
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Given that length of rectangle is 8 cm, Breadth of rectangle is 4 cm,side of square is 3 cm,base of right angled triangle is 3 cm,height of triangle is 5 cm.
Area of figure=Area of rectangle+Area of square+Area of triangle
Area of rectangle=length*breadth
Area of square=Side*Side
Area of triangle=1/2 *Base*Height
Area of figure=8*4+3*3+1/2 *3*5
=32+9+1/2 *15
=41+15/2
=(82+15)/2
=97/2
=48.5 
Hence if length of rectangle is 8 cm, breadth is 4 cm, side of square is 3 cm, base of triangle is 3 cm, then the area of figure will be 48.5
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2.) 3
3.) 3723
4.) 1512
5.)4692
6.)5525
7.) 760
8.) 696
Answer:
with what exactly
Step-by-step explanation:
Step-by-step explanation:
solution
let,A(5,-1)
given
y=12x-1
or, y = 12 × x + (-1)
comparing it with y=mx+c
we get
x=1
y = c = -1
now
A(5,-1) and B(1,-1)
equation of line is,
(y-y1)/(x-x1) = (y2-y1)/(x2-x1)
or, (y+1)/(x-5) = (-1+1)/(1-5)
or, (y+1)/(x-5) = 0/-4
cross multiply
-4y-4 = 0
or, 0=4y+4
or, 4y+4=0 is the required eqn
I think this is the process and answer too.
I hope this helps you