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SashulF [63]
3 years ago
13

Machine A can fill an order of widgets in a hours. Machine B can fill the same order of widgets in b hours. Machines A and B beg

in to fill an order of widgets at noon, working together at their respective rates. If a and b are even integers, is Machine A's rate the same as that of Machine B?(1) Machines A and B finish the order at exactly 4:48 p.m.(2) (a + b)^2 = 400
Mathematics
1 answer:
ycow [4]3 years ago
6 0

Answer:

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.

Step-by-step explanation:

Consider the provided information.

Machine A can fill an order of widgets in a hours. Machine B can fill the same order of widgets in b hours.

Thus, in 1 hr machine A's work is 1/a and machine B's work is 1/b.

We need to find whether the Machine A's rate the same as that of Machine B?

Statement 1: Machines A and B finish the order at exactly 4:48 p.m.

Total time, A and B worked = 4:48 = 4+\frac{48}{60} hrs = 4+\frac{4}{5} hrs= \frac{24}{5} hours

Thus, \frac{1}{a}+\frac{1}{b} = \frac{5}{24}

Let say Machine A's rate the same as that of Machine B

\frac{1}{a}+\frac{1}{a} = \frac{5}{24}\\\\\frac{2}{a} = \frac{5}{24}\\\\a = \frac{48}{5}

It is given that a and b are even integers, but \frac{48}{5} is not an even integer.

Hence, Machine A's rate is not same as that of Machine B.

Therefore, statement (1) ALONE is sufficient.

Statement 2: (a + b)^2 = 400

(a+b)^2 = 400\\a+b=20

There are many possible case in which a and b are even integer and there sum is 20.

If a = b = 10 (both even), then Machine A's rate is same as that of Machine B.

if a = 6 and b = 14 (both even), then Machine A's rate is not same as that of Machine B.

Therefore, No unique answer with statement 2.

Hence, statement 2 alone is not sufficient.

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