Answer:
the 2nd one
Step-by-step explanation:
Answer:
Step-by-step explanation:
From the given information; Let's assume that R should represent the set of all possible outcomes generated from a bit string of length 10 .
So; as each place is fitted with either 0 or 1

Similarly; the event E signifies the randomly generated bit string of length 10 does not contain a 0
Now;
if a 0 bit and a 1 bit are equally likely
The probability that a randomly generated bit string of length 10 does not contain a 0 if bits are independent and if a 0 bit and a 1 bit are equally likely is;

so ; if bits string should not contain a 0 and all other places should be occupied by 1; Then:
; 

Answer:
x = 12
consider this a straight line:
A B C
-------------------------------------------------
<u>solve for AB</u>:
⇒ AB = AC - BC
⇒ AB = 2x - 7 - ( x - 3 )
⇒ AB = 2x - x - 7 + 3
⇒ AB = x - 4
<u>solve for x</u>:
⇒ x - 4 = 8
⇒ x = 8 + 4
⇒ x = 12