Csc (x) = sec ( 90 - x) so csc(52) = sec (90 - 52) = sec (38)
Answer: From the 60° angle, the flagpole is the opposite side and the shadow is the adjacent side of the triangle.
tangent 60° = opposite/adjacent
so
tan 60° = 20/x
multiply both sides by x and you have
x · tan60° = 20
divide both sides by tan 60° and you have
x = 20/tan60°
x = 11.5 ft.
if this is wrong sorry don’t be mad but if it’s right then hope this helps
Answer:
100 hours
Step-by-step explanation:
can i get brainlist
It seems it should be the other way... . How soon will the puppy catch up with the kitten.
The way you have it the kitten will never catch the pup. There is already 180m between them so, the distance will only increase because the puppy runs faster than the cat.
If the puppy runs after the cat, will eventually catch up with it and can be calculated. Not the other way around.
If the pup runs after the cat, the distance between them will decrease and the pup will catch the cat.
RT = D kitten
RT = D+180 puppy
20T = D
25T = D + 180
Substitution
25T = 20T +180
5T = 180
T = 36s
