Answer:
l think 3rd option must be answer
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3x+12y+4 -- is the simplified version, variables would be x and y
Step-by-step explanation:
(2,4)===(4,-2)
(4,3)===(3,-4)
(2,3)===(3,-2)
Parameterize by the vector function
so that the normal vector to is given by
with magnitude
In this case, the normal vector is
with magnitude . The integral of over is then
where is the region in the plane over which is defined. In this case, it's the triangle in the plane which we can capture with and , so that we have
3y^2 - (y + 2) (y - 2) = 0
<=> 3y^2 - (y^2 - 4) = 0
<=> 2y^2 + 4 =0
<=>y^2 + 2 = 0
=> Because y^2 is always equal or larger than 0, there is no real solution.
Hope this helps!
:)