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AysviL [449]
4 years ago
10

Factor the binomial 3v-48​

Mathematics
2 answers:
lorasvet [3.4K]4 years ago
6 0

Answer:

3(v-16)

Step-by-step explanation:

3v-48 = 3(v-16)

divide 3v and 48 by 3

hjlf4 years ago
6 0

Answer:

3(v-16)

Step-by-step explanation:

Factor out a Greatest Common Factor or GCF

In this case, the GCF is 3

3v-48

3(v-16)

Hope this helps! :)

You might be interested in
The area of the circle is 249 square feet. find the diameter
bulgar [2K]

Answer:

2 x \sqrt{\frac{249}{\pi } } ft or 17.8055 ft

Step-by-step explanation:

Area=\pi r^{2}

249=\pi r^{2}

Solve for r.

r=\sqrt{\frac{249}{\pi } }

Multiply by 2 to get diameter.

6 0
3 years ago
Growth Models 19515. In 1968, the U.S. minimum wage was $1.60 per hour. In 1976, the minimum wagewas $2.30 per hour. Assume the
VikaD [51]

In general, the exponential growth function is given by the formula below

f(x)=a(1+r)^x

Where a and r are constants, and x is the number of time intervals.

In our case, n=0 for 1960; therefore, 1968 is n=8,

\begin{gathered} f(8)=a(1+r)^8 \\ \text{and} \\ f(8)=1.6 \\ \Rightarrow1.6=a(1+r)^8 \end{gathered}

And 1976 is n=16

\begin{gathered} f(16)=a(1+r)^{16} \\ \text{and} \\ f(16)=2.3 \\ \Rightarrow2.3=a(1+r)^{16} \end{gathered}

Solve the two equations simultaneously, as shown below

\begin{gathered} \frac{1.6}{(1+r)^8}=a \\ \Rightarrow2.3=\frac{1.6}{(1+r)^8}(1+r)^{16} \\ \Rightarrow2.3=1.6(1+r)^8 \\ \Rightarrow\frac{2.3}{1.6}=(1+r)^8 \\ \Rightarrow(\frac{2.3}{1.6})^{\frac{1}{8}}=(1+r)^{}^{} \\ \Rightarrow r=(\frac{2.3}{1.6})^{\frac{1}{8}}-1 \\ \Rightarrow r=0.0464078 \end{gathered}

Solving for a,

\begin{gathered} r=0.0464078 \\ \Rightarrow a=\frac{1.6}{(1+0.0464078)^8}=1.113043\ldots \end{gathered}

a) Thus, the equation is

\Rightarrow f(n)=1.113043\ldots(1+0.0464078\ldots)^n

b) 1960 is n=0; thus,

f(0)=1.113043\ldots(1+0.0464078\ldots)^0=1.113043\ldots

The answer to part b) is $1.113043... per hour

c)1996 is n=36

\begin{gathered} f(36)=1.113043\ldots(1+0.0464078\ldots)^{36} \\ \Rightarrow f(36)=5.6983\ldots \end{gathered}

The model prediction is above $5.15 by $0.55 approximately. The answer is 'below'

4 0
1 year ago
A grocer is mixing 40 cent per pound coffee with 60 cent per pound coffee to make a mixture worth 54 cents per
Grace [21]
It’s definitely 50 :)
7 0
4 years ago
Can you help me answer this question
r-ruslan [8.4K]
Division of a fraction is the equivalent of multiplying by its reciprocal
ex.
\frac{\frac{A}{B} }{\frac{C}{D}}=\frac{A}{B} *\frac{D}{C}
i suggest you try to remember this concept

in terms of your question

\frac{\frac{4c-12}{4c+8}}{\frac{c-3}{c^2-4}}= \frac{4c-12}{4c+8} *\frac{c^2 -4}{c-3}

from this point, just multiple the numerators together and denominators together, then simplify if necessary

fyi- difference of squares
x^2-b^2 = (x-b)(x+b)
relating that to
c^2-4 = c^2 -2^2 = (c-2)(c+2)

also a side note, you might want to factor out the 4 first in the top fraction


4 0
4 years ago
A veterinarian’s assistant made a table that shows the animals seen in the office in one week. What is the probability that the
horsena [70]

Answer:

The probability that the pet seen was sick is 53.57%.

Step-by-step explanation:

The probability of an event <em>E</em> is the ration of the number of favorable outcomes to the total number of outcomes.

P(E)=\frac{n(E)}{N}

Here,

n (E) = number of favorable outcomes

N = total number of outcomes

Denote the events as follows:

<em>C</em> = the pet is a cat

<em>D</em> = the pet is a dog

<em>O </em>=<em> </em>the pet is some other animal

<em>S</em> = the pet is sick.

The data provided is summarized as follows:

n (C) = 28

n (C ∩ S) = 3

n (D) = 42

n (B ∩ S) = 4

n (O) = 24

n (O ∩ S) = 8

Compute the probability that a cat was sick as follows:

P(C\cap S)=\frac{n(C\cap S)}{n(C)}=\frac{3}{28}

Compute the probability that a dog was sick as follows:

P(D\cap S)=\frac{n(D\cap S)}{n(D)}=\frac{4}{42}=\frac{2}{21}

Compute the probability that another animal was sick as follows:

P(O\cap S)=\frac{n(O\cap S)}{n(O)}=\frac{8}{24}=\frac{1}{3}

Compute the probability that the pet seen was sick as follows:

P (S) = P (C ∩ S) + P (D ∩ S) + P (O ∩ S)

       =\frac{3}{28}+\frac{2}{21}+\frac{1}{3}\\=\frac{9+8+28}{84}\\=\frac{45}{84}\\=0.5357

Thus, the probability that the pet seen was sick is 53.57%.

8 0
4 years ago
Read 2 more answers
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