Answer:
(8x2−4x−8)(2x+3x+2)
=(8x2+−4x+−8)(2x+3x+2)
=(8x2)(2x)+(8x2)(3x)+(8x2)(2)+(−4x)(2x)+(−4x)(3x)+(−4x)(2)+(−8)(2x)+(−8)(3x)+(−8)(2)
=16x3+24x3+16x2−8x2−12x2−8x−16x−24x−16
=40x3−4x2−48x−16
Step-by-step explanation:
<span>Answer:
We'll have to integrate the growth rate with respect to time, without forgetting the amount of area covered at the start.
A = 2010 + â« 8t1/2 dt (as t goes from 0 to 24)
A = 2010 + [(16/3) t3/2] (as t goes from 0 to 24)
A = 2010 + 627 = 2637 acres
We don't integrate the 2010 here because whatever effects of the passing of time have already taken place over that area. We just treat it as a constant and add it to the result of integration.</span>
I believe this is the right way to write the function
N = [log A − log P] / log(1.0175)
N =[ log (1210.26) - log (1000)]/log (1.0175)
N =log [1210.26/1000] / log (1.0175) = log (1.21026)/log(1.0175) = 0.08288/0.00753 = 11
N = 11 months
Answer:
Hence the value for the mean is 80 and the standard deviation for the original sample is 8.
Step-by-step explanation:
Mean = 83-3 = 80.
Here the standard deviation didn't change = 8.
