Answer:
given, mother and father are heterozygotes.
let, father has B blood group and mother has A blood group.
then their heterozygous genotypes are --
father = iB, iO and mother = iA, iO
punnett square will be,
iB iO
iA iA iB iA iO
iO iB iO iO iO
the genotypes of their progeny will be, iAiB , iAiO ,iBiO and iOiO
and phenotypes will be 3 are heterozygous and 1 is homozygous.
The correct answer is <span>C. You cannot view live specimens because the necessary preparation kills cells. </span>
The answer is pretty self-explanatory. Unlike it, regular microscopes can view living creatures such as bacteria or similar.
i think that before the Krebs cycle begins, pyruvic acid, which has three carbon atoms, is split apart and combined with an enzyme known as CoA.
Answer:
B.
Explanation: Hope this helps! ^^