A. The equation to find the distance of the flowerbed from the hive is:
, where x is the distance.
B. The flowerbed is 2250 feet far from the hive.
<u><em>Explanation</em></u>
Suppose, the distance of the flowerbed from the hive is
feet.
The bee flies 20 feet per second directly to a flowerbed from its hive and flies directly back to the hive at 12 feet per second.
As,
So, the time taken by the bee to reach the flowerbed
seconds and the time taken to fly back to the hive
seconds.
The bee stays at the flowerbed for 15 minutes or (15×60)seconds or 900 seconds and it is away from the hive for a total of 20 minutes or (20×60)seconds or 1200 seconds.
So, the equation will be.......

Thus, the distance of the flowerbed from the hive is 2250 feet.
Y=3x2+1
Hope this helped :)
Answer:
98child tickets were sold that day
Step by step Explanation:
Let the number of children= A of the number of adult
Then
6.20C + 9.50A = 1082.0
From the question it was said that four times as many adult tickets as child tickets were sold which implies that number of adult was FOUR times the children, then we can say
A= 4C
Then substitute into the above equation
6.20C + 9.50A = 1082.0
6.20C + 9.50(4C) = 1082.0
6.20C + 38C= 1082.0
44.2C =1082.0
C= 24.48
But we know that
A= 4C
A=4* 24.48
A= 97.9
Therefore ,98child tickets were sold that day