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3 years ago

-10=x/2+6 Answers -8 -14 -32 18

Mathematics

1 answer:

Yanka [14]3 years ago

6 0

Answer:

$x=-32$

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Let a and b be roots of x² - 4x + 2 = 0. find the value of a/b² +b/a²

erastovalidia [21]

Answer:

$\dfrac{a}{b^2}+\dfrac{b}{a^2}=10$

Step-by-step explanation:

Given equation: $x^2-4x+2=0$

The roots of the given quadratic equation are the values of x when $y=0$ .

To find the roots, use the quadratic formula:

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=1, \quad b=-4, \quad c=2$

$\begin{aligned}\implies x & =\dfrac{-(-4) \pm \sqrt{(-4)^2-4(1)(2)}}{2(1)}\\& =\dfrac{4 \pm \sqrt{8}}{2}\\& =\dfrac{4 \pm 2\sqrt{2}}{2}\\& =2 \pm \sqrt{2}\end{aligned}$

$\textsf{Let }a=2+\sqrt{2}$

$\textsf{Let }b=2-\sqrt{2}$

Therefore:

$\begin{aligned}\implies \dfrac{a}{b^2}+\dfrac{b}{a^2} & = \dfrac{2+\sqrt{2}}{(2-\sqrt{2})^2}+\dfrac{2-\sqrt{2}}{(2+\sqrt{2})^2}\\\\& = \dfrac{2+\sqrt{2}}{6-4\sqrt{2}}+\dfrac{2-\sqrt{2}}{6+4\sqrt{2}}\\\\& = \dfrac{(2+\sqrt{2})(6+4\sqrt{2})+(2-\sqrt{2})(6-4\sqrt{2})}{(6-4\sqrt{2})(6+4\sqrt{2})}\\\\& = \dfrac{12+8\sqrt{2}+6\sqrt{2}+8+12-8\sqrt{2}-6\sqrt{2}+8}{36+24\sqrt{2}-24\sqrt{2}-32}\\\\& = \dfrac{40}{4}\\\\& = 10\end{aligned}$

6 0

2 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=4%20-%20%20%5Cfrac%7B2%7D%7B3%7Dx%20%3D%20%20%5Cfrac%7Bx%20-%206%7D%7B5%7D%20" id="TexFormula1

morpeh [17]

4-2/3x=x-6/5

Answer: X=6

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3 years ago

I need the answer asap please hurry i give you 5 stars

Misha Larkins [42]

Answer: -3, -2.5, -1, 2, 5.

Explanation:
The number line goes from the smallest number to the largest number. As an example you may ask why -3 is smaller than -1 even though it looks larger. This is because it actually isn’t since it is negative. When a number is negative, the higher the number are the smaller it is. One more example could be that -10 is smaller than -5.

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3 years ago

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3a+a+2a-5a? Can someone give me the answer please? Ty

Shkiper50 [21]

Answer:

Step-by-step explanation:

=3a + a + 2a - 5a

=4a - 3a

= a

hope it helps u tate!

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