If mutation is associated with the centromere region, the direct impact would be on the segregating mechanism during cell division process.
Answer:
Each FADH2 yields about 1.5 ATP via oxidative phosphorylation.
Explanation:
Most of the ATP molecules are produced by oxidative phosphorylation, not by substrate-level phosphorylation. During glycolysis, 2 ATP molecules per glucose are produced by substrate-level phosphorylation. Similarly, Kreb's cycle also yields 2 ATP per glucose by substrate-level phosphorylation.
For each pair of electrons transferred to O2 from FADH2 via electron transport chain, 4 and 2 protons are pumped from matrix towards the intermembrane space by complex III and complex IV respectively. It generates the proton concentration gradient required to drive the synthesis of 1.5 ATP molecules. Since oxidation of FADH2 is coupled to the phosphorylation of ADP to form ATP, the process is called oxidative phosphorylation.
Answer:
C low competition for glucose
Explanation:
From the given answer choices and information,
It cannot be A since there is no visual disease or any indication of disease in the experiment
Cannot be B, since space would not be an issue since it clearly hit 111 on day 3
and cannot be D since there is no indication of a change in temperature.
However, we know Petri Dishes have nutrients to stimulate cell growth, and those resources are not unlimited therefore we can only attest that a large portion of the nutrients have been consumed and starved some of the cells thus causing a population decrease
<span>Insulin lispro is a mealtime insulin which is rapid-acting. Insulins are taken 15 minutes before or 15 minutes after. If a client is </span><span>scheduled to get a breakfast tray at 07:00, the client must receive a prescribed dose of insulin lispro at 6:45 or 7:15. </span>
Answer:
....I think you should give us the scenarios first so that we can help you.