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love history [14]

3 years ago

8

In a survey 7/8 of the people surveyed said that recycling is important. Only 1/2 of them buy products made with recycled materi

als. What fraction of the respondents buy products made with recycled materials?

1 answer:

morpeh [17]3 years ago

5 0

Answer:

only 3.5 buy products made with recycled material but you have to round it to 4

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Which of the following so an equivalent expression to the expression a1/3/a1/4?

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How many square inches does an 11" x 13" area encompass?

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4 years ago

A label wraps around soup can with a radius of 4.3 cm and a height of 6 cm. What is the lateral surface area of the label of the

Soloha48 [4]

Answer:

$52\pi \text{ cm}^2\approx 162.11\text{ cm}^2$

Step-by-step explanation:

We have been given that a label wraps around soup can with a radius of 4.3 cm and a height of 6 cm. We are asked to find the lateral surface area of the label of the soup can in square centimeters.

We will use lateral surface area of cylinder to solve our given problem as:

$LA=2\pi rh$ , where,

r = Radius of cylinder,

h = height of cylinder.

Upon substituting our given values in above formula, we will get:

$LA=2\pi \times\text{4.3 cm}\times \text{6 cm}$

$LA=51.6\pi \text{ cm}^2$

$LA=162.10618\text{ cm}^2$

Therefore, the lateral surface area of the label of the soup is approximately 162.11 square cm.

5 0

4 years ago

Read 2 more answers

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

4 0

2 years ago