All categories

3 years ago

What quadrilateral has at least one pair of parallel sides but isn't a parallelogram

Mathematics

2 answers:

Sedbober [7]3 years ago

7 0

A trapezium has a pair of parallel sides.

timama [110]3 years ago

5 0

It's a trapezoid because 2 of the sides are parallel and 2 are not.

You might be interested in

Write down the missing number in the following 1,,4,9,16,25,?

ludmilkaskok [199]

Answer:

Step-by-step explanation:

you know the number based on the sequence

the values increase in the form of x+2

e.g. 4-1=3

9-4=5

16-9=7

25-16=9

you can see the number adds 2 for every increased number

and by following this sequence you will get the number 36

3 0

4 years ago

Read 2 more answers

What is the surface area of a square pyramid that has a base length of 5 inches and triangular faces that are 9 inches tall

scZoUnD [109]

Answer:

115 in²

Step-by-step explanation:

SA = Area of triangular surfaces + area of the square base

SA= 2bh + b²

SA = 2(5)(9)+5²

SA = 90+25

SA = 115

7 0

3 years ago

All of the following effect the wind motion EXCEPT

iVinArrow [24]

Answer:

I think option D.

Step-by-step explanation:

lmk if it's wrong

7 0

3 years ago

Perform the indicated operations. Write the answer in standard form, a+bi.<br> 5-3i / -2-9i

Vsevolod [243]

$\huge \boxed{\mathfrak{Answer} \downarrow}$

$\large \bf\frac { 5 - 3 i } { - 2 - 9 i } \\$

Multiply both numerator and denominator of $\sf \frac{5-3i}{-2-9i} \\$ by the complex conjugate of the denominator, -2+9i.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2-9i\right)\left(-2+9i\right)}) \\$

Multiplication can be transformed into difference of squares using the rule: $\sf\left(a-b\right)\left(a+b\right)=a^{2}-b^{2}$ .

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{\left(-2\right)^{2}-9^{2}i^{2}}) \\$

By definition, i² is -1. Calculate the denominator.

$\large \bf \: Re(\frac{\left(5-3i\right)\left(-2+9i\right)}{85}) \\$

Multiply complex numbers 5-3i and -2+9i in the same way as you multiply binomials.

$\large \bf \: Re(\frac{5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9i^{2}}{85}) \\$

Do the multiplications in $\sf5\left(-2\right)+5\times \left(9i\right)-3i\left(-2\right)-3\times 9\left(-1\right)$ .

$\large \bf \: Re(\frac{-10+45i+6i+27}{85}) \\$

Combine the real and imaginary parts in -10+45i+6i+27.

$\large \bf \: Re(\frac{-10+27+\left(45+6\right)i}{85}) \\$

Do the additions in $\sf-10+27+\left(45+6\right)i$ .

$\large \bf Re(\frac{17+51i}{85}) \\$

Divide 17+51i by 85 to get $\sf\frac{1}{5}+\frac{3}{5}i \\$ .

$\large \bf \: Re(\frac{1}{5}+\frac{3}{5}i) \\$

The real part of $\sf \frac{1}{5}+\frac{3}{5}i \\$ is $\sf \frac{1}{5} \\$ .

$\large \boxed{\bf\frac{1}{5} = 0.2} \\$

3 0

3 years ago

HELP ASAP PLEASE GIVING BRAINLIEST!!

Sholpan [36]

Answer:

$0.51 = 0.51 in decimal form

Step-by-step explanation:

3 0

3 years ago