The value of the collection originally was $1,000,000
What was the original value of the collection?
The original value of the collection is not known, hence, it is represented by X
The increase in value by $50,000 means that the value is X+$50,000
Now, when the error was discovered, it is now worth half of the value previously
The new value is (X+$50,000)*0.5
New value=(X+$50,000)*0.5
The new value at this point is $525,000
$525,000=(X+$50,000)*0.5
$525,000/0.5=X+$50,000
$1,050,000=X+$50,000
X=$1,050,000-$50,000
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Answer:
Yes
Step-by-step explanation:
First, suppose that nothing has changed, and possibility p is still 0.56. It's our null hypothesis. Now, we've got Bernoulli distribution, but 30 is big enough to consider Gaussian distribution instead.
It has mean μ= np = 30×0.56=16.8
standard deviation s = √npq
sqrt(30×0.56×(1-0.56)) = 2.71
So 21 is (21-16.8)/2.71 = 1.5494 standard deviations above the mean. So the level increased with a ˜ 0.005 level of significance, and there is sufficient evidence.
Equation- p-6= -14
Answer- p=-14
Answer:
y = -3/4x -5
Step-by-step explanation:
The slope always goes first, then variable x and the y intercept comes last
Answer:
2520 gallons
Step-by-step explanation:
3000 gallons -780 gallons drained over 6 hours then add 300 gallons over three hours = 2520 gallons
