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NemiM [27]
3 years ago
7

Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced

before the second ball is drawn, the outcomes of the experiment are equally likely. List all 25 possible outcomes of the experiment on a sheet of paper.Consider the event that the first ball that is drawn is blue.

Mathematics
1 answer:
Sati [7]3 years ago
6 0

Answer:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

Step-by-step explanation:

\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls},(denoted \:W_1, W_2, \:and\: W_3)

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and  its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

The tree diagram of this event is also attached.

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Use the percent formula, A = PB, where A is P percent of B, to answer the following question. What is 24% of 60?
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It should be noted that 24 percent of 60 is 14.4.

<h3>How to calculate the percentage?</h3>

The question is to calculate 24% of 60.

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Step-by-step explanation:

We cannot tell from the posted picture whether the boundary line is solid or dashed, so the answer above is split into two parts. If the boundary line is solid (x+2y≥20), all three listed points are in the solution set. If the boundary line is dashed (x+2y>20), only (100, 100) is in the solution set.

8 0
3 years ago
Read 2 more answers
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