What statement could be used to explain why f(x)=2x-3 has an inverse relation that is a function

For the question: "My quadrilateral has a pair of equal sides and a pair of parallel sides, what special type my quadrilateral m

Effectus [21]

Answer:

Step-by-step explanation:

It must be a trapezoid because a trapezoid has at least one set of parallel sides. Sides of equal length don't mean anything really unless we know hose sides are parallel. I will say sometimes I hear trapezoids ONLY have two parallel sides, while the other two are not, while in other places as long as two are parallel it is a trapezoid. It looks like for this question it is using the definition that at least two parallel sides makes it a trapezoid.

it can be an isosceles trapezoid since it is a type of trapezoid, same with right trapezoid. Basically any special kind of trapezoid

parallelogram because it can have two pairs of parallel lines and have thos parallel sides be equal. So this also means it can be all kinds of parallelograms.

Do you have a list to choose from? because most I pull up don't include right trapezoid at least.

This leaves kite as the only kind of quadrilateral to look at yet, and it specifies no parallel sides. bt your shape need at least one set of them, so it cannot be a kite.

8 0

2 years ago

If the second number is subtracted from the sum of the first number and 2 times the third number, the result is 1. The thrid num

weeeeeb [17]

Answer:

Step-by-step explanation:

$x,\ y,\ z-\text{three numbers}\\\\\left\{\begin{array}{ccc}(x+2z)-y=1&(1)\\z+2x=3&(2)\\x+3y+z=18&(3)\end{array}\right\\\\(2)\\z+2x=3\qquad\text{subtract}\ 2x\ \text{from both sides}\\z=3-2x\qquad(*)\\\\\text{Substitute}\ (*)\ \text{to (1) and (3)}\\\\\left\{\begin{array}{ccc}x+2(3-2x)-y=1&\text{use the distributive property}\\x+3y+(3-2x)=18\end{array}\right$

$\left\{\begin{array}{ccc}x+(2)(3)+(2)(-2x)-y=1\\x+3y+3-2x=18&\text{subtract 3 from both sides}\end{array}\right\\\left\{\begin{array}{ccc}x+6-4x-y=1&\text{subtract 6 from both sides}\\(x-2x)+3y=15\end{array}\right\\\left\{\begin{array}{ccc}(x-4x)-y=-5\\-x+3y=15\end{array}\right\\\left\{\begin{array}{ccc}-3x-y=-5&\text{multiply both sides by 3}\\-x+3y=15\end{array}\right$

$\underline{+\left\{\begin{array}{ccc}-9x-3y=-15\\-x+3y=15\end{array}\right}\qquad\text{add all sides of the equations}\\.\qquad-10x=0\qquad\text{divide both sides by (-10)}\\.\qquad\boxed{x=0}\\\\\text{Put it to the second equation:}\\-0+3y=15\\3y=15\qquad\text{divide both sides by 3}\\\boxed{y=5}\\\\\text{Put the value of}\ x\ \text{to}\ (*):\\\\z=3-2(0)\\\boxed{z=3}$