Question

Measurements show that the enthalpy of a mixture of gaseous reactants increases by 130. kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that -137. kJ of work is done on the mixture during the reaction.

Answer 1

Answer:

167 kJ

Explanation:

Given parameters

Change in enthalpy = 130 kJ (decrease)

Work done = -137 kJ

Change in energy, \delta = ?  

From the first law of thermodynamics:

ΔH = ΔE + PΔV,

Where, ΔH= change in enthalpy

ΔE = change in Internal energy  

Substituting values into the above formula —  

130 kJ = ΔE + -137  kJ

130 kJ = ΔE - 137 kJ

therefore,

ΔE = (130 + 137 ) kJ

ΔE = 167 kJ

Therefore, the change in energy of the gas mixture during the reaction is 167 kJ.  

Since the value of energy change Is positive, therefore this Is endothermic reaction