<u>Answer:</u> The amount of water that can be formed is 160 moles
<u>Explanation:</u>
We are given:
Moles of hydrogen gas = 170 moles
Moles of oxygen gas = 80 moles
The chemical equation for the reaction of hydrogen gas and oxygen gas follows:
By Stoichiometry of the reaction:
1 mole of oxygen gas reacts with 2 moles of hydrogen gas
So, 80 moles of oxygen gas will react with = 
of hydrogen gas
As, given amount of hydrogen gas is more than the required amount. So, it is considered as an excess reagent.
Thus, oxygen gas is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of oxygen gas produces 2 moles of water
So, 80 moles of oxygen gas will produce = 
of water
Hence, the amount of water that can be formed is 160 moles
Answer:
2. 181.25 K.
3. 0.04 atm.
Explanation:
2. Determination of the temperature.
Number of mole (n) = 2.1 moles
Pressure (P) = 1.25 atm
Volume (V) = 25 L
Gas constant (R) = 0.0821 atm.L/Kmol
Temperature (T) =?
The temperature can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
1.25 × 25 = 2.1 × 0.0821 × T
31.25 = 0.17241 × T
Divide both side by 0.17241
T = 31.25 / 0.17241
T = 181.25 K
Thus, the temperature is 181.25 K.
3. Determination of the pressure.
Number of mole (n) = 10 moles
Volume (V) = 5000 L
Temperature (T) = –10 °C = –10 °C + 273 = 263 K
Gas constant (R) = 0.0821 atm.L/Kmol
Pressure (P) =?
The pressure can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
P × 5000 = 10 × 0.0821 × 263
P × 5000 = 215.923
Divide both side by 5000
P = 215.923 / 5000
P = 0.04 atm
Thus, the pressure is 0.04 atm
Both are caused by human ignorance. Both have the ability to kill those in them. Both can become compact to create new material.
Explanation:
According to the Handerson equation,
pH = 
or, pH = 
Putting the given values into the above equation as follows.
pH =
5.0 = 6.0 + log \frac{\text{conjugate base}}{\text{acid}}[/tex]
= -1.0
or, 
= 0.1
Therefore, we can conclude that molar ratios of conjugate base to weak acid for given solution is 0.1.
Answer:
2.7 x 10^-19 J
Explanation:
The formula needed for this problem is
E = hν
where E = energy, h = Planck's constant = 6.626x10^-34 and ν is the frequency
c = λν
where c = speed of light = 3x10^8, and λ = wavelength
3x10^8 = 7.35x10^-7 . ν
ν = 4.08 x 10^14 Hz
E = 6.626x10^-34 . 4.08x10^14 = 2.7 x 10^-19 J
