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3 years ago

How many square inches of the pizza is left over

Mathematics

2 answers:

Kisachek [45]3 years ago

7 0

So first we need to find the area of pizza which is pir^2 radius is 9 so 81pi
Now we need to find area of pizza slice triangle amd subtract its area from pizzas area
Triangles area is (9x5)/2 =22.5
So answer is 81pi-22.5 is left
I think its correct

romanna [79]3 years ago

7 0

D=18 inches
r=9 inches
A=9×9×π
A=81π
A≈254.34 square inches

A of the rectangle=l×w
or
A=B×h
A= 9×5
A=45 sqaure inches.

254.34-45= 209.34. As a result, there are about 209.34 square inches of pizza that are left over. Hope it help!

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Step 2: Using quadratic equation solve for y

$\begin{gathered} y^2+2\sqrt[]{3}y-1=0 \\ y=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ a=1,b=2\sqrt[]{3},c=-1 \\ y=\frac{-2\sqrt[]{3}\pm\sqrt[]{(2\sqrt[]{3})^2-4(1)(-1)}}{2(1)} \\ y=\frac{-2\sqrt[]{3}\pm\sqrt[]{12+4}}{2} \\ y=\frac{-2\sqrt[]{3}\pm\sqrt[]{16}}{2} \\ y=\frac{2(-\sqrt[]{3}\pm2)}{2} \\ y=-\sqrt[]{3}\pm2 \end{gathered}$

Since the y represents tan x

$\begin{gathered} \tan \mleft(x\mright)=-\sqrt{3}-2,\: \tan \mleft(x\mright)=2-\sqrt{3} \\ x=\arctan \mleft(-\sqrt{3}-2\mright)+\pi n,\: x=\arctan \mleft(2-\sqrt{3}\mright)+\pi n \\ x\text{ in degrees} \\ \: x=-75^{\circ\: }+180^{\circ\: }n,\: x=15^{\circ\: }+180^{\circ\: }n \\ \: x=15^{\circ\: }+180^{\circ\: }n \end{gathered}$

Therefore the correct answer is

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