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3 years ago

How many square inches of the pizza is left over

Mathematics

2 answers:

Kisachek [45]3 years ago

7 0

So first we need to find the area of pizza which is pir^2 radius is 9 so 81pi
Now we need to find area of pizza slice triangle amd subtract its area from pizzas area
Triangles area is (9x5)/2 =22.5
So answer is 81pi-22.5 is left
I think its correct

romanna [79]3 years ago

7 0

D=18 inches
r=9 inches
A=9×9×π
A=81π
A≈254.34 square inches

A of the rectangle=l×w
or
A=B×h
A= 9×5
A=45 sqaure inches.

254.34-45= 209.34. As a result, there are about 209.34 square inches of pizza that are left over. Hope it help!

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ANSWER

The point is
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The vertical line
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and the horizontal line
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will intersect at
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This is the unique solution to the two equations.

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3 years ago

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3 years ago

Make 'h' as the subject. Remember to rationalize the denominator while solving.

Sliva [168]

Hello there BeGuiLE !

To solve your question, we must first bring 'h' to one side of the equation. Let's bring all the terms with the variable 'h' to the left side of the equation. So,
$\large{\sf\sqrt{ 3 } h = 1.6+h}$
→ $\large{\sf\sqrt{3}h-h=1.6 }$

Now, let's combine the 2 terms containing the variable 'h'.
$\large{\sf\sqrt{3}h-h=1.6 }$
→ $\large{\sf\left(\sqrt{3}-1\right)h=1.6 }$

Now, we need to leave the variable 'h' alone in the left side of the equation & bring (√3 + 1) to the other side of the equation. This is done in order to make 'h' as the subject of the equation. So, we'll get it as,
$\large{\sf\left(\sqrt{3}-1\right)h=1.6 }$
→ $\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }$

Now, let's rationalize it. Rationalizing is a process where we move the root from the denominator of a fraction to the numerator for easier calculation. So,
$\large{\sf\:h=\frac{1.6}{\sqrt{3}-1} }$
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{(\sqrt{3}-1 )(\sqrt{3}+1}) }$
Now, use the algebraic identity, (a + b)(a - b) = a² - b²
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{3-1} }$
→ $\large{\sf\:h=\frac{1.6(\sqrt{3}+1)}{2} }$
→ $\boxed{\large{\sf\:h=0.8(\sqrt{3}+1)}}$

Now, we've made 'h' as the subject of the equation. If you want to solve it more, then,
$\large{\sf\:h=0.8(\sqrt{3}+1)}$
Take √3 as 1.73 (approx. value up to 2 decimal places)
→ $\large{\sf\:h=0.8(1.73+1)}$
→ $\large{\sf\:h=0.8(2.73)}$
→ $\boxed{\boxed{\huge{\bf{\:h=2.184 \: (approx.)}}}}$

I hope this will help you.

Please refer to the attached image if the explanation shows some error.

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Check out more links which will help you understand the topic better :

■ brainly.com/question/21406377

■ brainly.com/question/696184

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