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amm1812
3 years ago
15

In the 30°-60°-90° triangle above, y = 6. Find the other two lengths.

Mathematics
1 answer:
Elodia [21]3 years ago
5 0

Answer:

d

Step-by-step explanation:

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3. Using techniques from Calculus, show directly that the maximum value of a 1-D Gaussian distribution occurs at the point x = μ
Vilka [71]

Answer:

For a scaler variable, the Gaussian distribution has a probability density function of

p(x |µ, σ² ) = N(x; µ, σ² ) = 1 / 2π×e^{\frac{-(x-u)^{2}}{2s^{2} }  }

The term will have a maximum value at the top of the slope of the 1-D Gaussian distribution curve that is when exp(0) =1 or when x = µ

Step-by-step explanation:

Gaussian distributions have similar shape, with the mean controlling the location and the variance controls the dispersion  

From the graph of the probability distribution function it is seen that the the peak is the point at which the slope = 0, where µ = 0 and σ² = 1 then solution for the peak = exponential function = 0 or x = µ

5 0
3 years ago
Enter your answer and show all the steps you use to solve this problem in the space provided. What is the volume of the rectangu
Dovator [93]

Answer: 416 mm

Step-by-step explanation: The equation for the volume of a rectangular prism is length*width*height. The width (5) times the height (8) is 40 (5*8=40). The volume is that (40) times the length(10.4) which is 416 (40*10.4=416).

3 0
3 years ago
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (g – f)(3)?
Oduvanchick [21]
Remember that (g-f)(x) is g(x)-f(x). We know form our problem that f(x)=4-x^2 and g(x)=6x, so:
(g-f)(x)=g(x)-f(x)
(g-f)(x)=6x-(4-x^2)
(g-f)(x)=6x-4+x^2

Now, to find (g-f)(3), we just need to evaluate (g-f)(x) at 3. In other words, we are going to replace x with 3:
(g-f)(x)=6x-4+x^2
(g-f)(x)=6(3)-4+(3)^2

We can conclude that the correct answer is <span>C.6(3) – 4 + 3^2 </span>

5 0
3 years ago
The total monthly profit for a firm is P(x)=6400x−18x^2− (1/3)x^3−40000 dollars, where x is the number of units sold. A maximum
wlad13 [49]

Answer:

Maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

Step-by-step explanation:

We are given the following information:P(x) = 6400x - 18x^2 - \frac{x^3}{3} - 40000, where P(x) is the profit function.

We will use double derivative test to find maximum profit.

Differentiating P(x) with respect to x and equating to zero, we get,

\displaystyle\frac{d(P(x))}{dx} = 6400 - 36x - x^2

Equating it to zero we get,

x^2 + 36x - 6400 = 0

We use the quadratic formula to find the values of x:

x = \displaystyle\frac{-b \pm \sqrt{b^2 - 4ac} }{2a}, where a, b and c are coefficients of x^2, x^1 , x^0 respectively.

Putting these value we get x = -100, 64

Now, again differentiating

\displaystyle\frac{d^2(P(x))}{dx^2} = -36 - 2x

At x = 64,  \displaystyle\frac{d^2(P(x))}{dx^2} < 0

Hence, maxima occurs at x = 64.

Therefore, maximum profits are earned when x = 64 that is when 64 units are sold.

Maximum Profit = P(64) = 2,08,490.666667$

6 0
3 years ago
At noon the temperature was 0°C. If the temperature then rose 3°C per hour, what was
lukranit [14]

Answer:

21 degrees

Step-by-step explanation:

4 0
3 years ago
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