Answer:
= 200 mL
Explanation:
Using the dilution formula;
M1V1 = M2V2 ;
Where, M1 is the concentration before dilution, V2 is the volume before dilution, while M2 is the concentration after dilution and V2 is the volume after dilution.
M1 = 2.0 M
V1 = 50 mL
M2 = 0.50 M
V2 = ?
V2 = M1V1/M2
= ( 2.0 × 50 )/ 0.5
= 200 mL
Therefore, the volume after dilution will be, 200 mL
<u>Answer:</u>
(a): The balloon will contain
number of molecules now.
(b): The gas law associated with this is Avogadro's law.
<u>Explanation:</u>
Avogadro's law states that the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature
Mathematically,
(At constant pressure and temperature)
OR
.....(1)
where,
= Initial volume and number of moles
= Final volume and number of moles
We are given:

Putting values in equation 1, we get:

(a):
If
number of moles of gas contains X number of molecules
So,
number of moles of gas will contain =
number of molecules
Hence, the balloon will contain
number of molecules now.
(b): The law used is Avogadro's law.
The answer is Ga.
That is gallium (Ga), correctly names the element that Mendeleev predicted would be discovered and placed in the aluminum column.
Gallium (Ga) is the element that Mendeleev predicted would be discovered and placed in the aluminum column.
So the answer is Gallium (Ga) that is there in the 13th group of periodic table or in aluminium column.
Answer:
1.33 kilograms of this liquid must be evaporated to freeze a tray of water at 0°C to ice at 0°C.
Explanation:
Let the mass of liquefied dichlorodifluoromethane be x.
Mass of water to freeze = 571 g
Moles of water =
Heat of fusion of ice = 6.02 kJ/mol
Heat lost when 1 mole of water freeze's = -6.02kJ/mol
Heat lost when 31.7 moles of water freeze's: Q

Heat required to evaporate x amount of liquefied dichlorodifluoromethane: Q'
Q'= -(Q) = 191. kJ
Moles of liquefied dichlorodifluoromethane =
Heat of vaporization of dichlorodifluoromethane = 17.4 kJ/mol


Solving for x:
x = 1328.2 g = 1.33 kg
1 g = 0.001 kg
1.33 kilograms of this liquid must be evaporated to freeze a tray of water at 0°C to ice at 0°C.