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prisoha [69]
3 years ago
5

An inflated balloon contains X air molecules.After some time the volume of the balloon is found to be the half at the same tempe

rature and pressure when a few air molecules are expelled out. a)How many molecules will be there in the balloon now? b) Which is the gas law associated with this?
Chemistry
1 answer:
astra-53 [7]3 years ago
8 0

<u>Answer:</u>

(a): The balloon will contain \frac{X}{2} number of molecules now.

(b): The gas law associated with this is Avogadro's law.

<u>Explanation:</u>

Avogadro's law states that the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature

Mathematically,

V\propto n                   (At constant pressure and temperature)

OR

\frac{V_1}{n_1}=\frac{V_2}{n_2}               .....(1)

where,

V_1\text{ and }n_1 = Initial volume and number of moles

V_2\text{ and }n_2 = Final volume and number of moles

We are given:

V_2=\frac{V_1}{2}

Putting values in equation 1, we get:

\frac{V_1}{n_1}=\frac{V_1}{2\times n_2}\\\\n_2=\frac{n_1}{2}

(a):

If n_1 number of moles of gas contains X number of molecules

So, \frac{n_1}{2} number of moles of gas will contain = \frac{X}{n_1}\times {n_1}{2}=\frac{X}{2} number of molecules

Hence, the balloon will contain \frac{X}{2} number of molecules now.

(b): The law used is Avogadro's law.

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