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Marizza181 [45]
2 years ago
7

Which is usually associated with a faster reaction rate? A. shaking pepper into the reactants B. removing heat energy from the r

eactants C. using a highly concentrated solution in the reactants D. using a solid with a low surface area in the reactants
Chemistry
1 answer:
Andrews [41]2 years ago
3 0

Answer:

C. Using a highly concentrated solution of the reactants  

Explanation:

If the solutions are more concentrated, there will be more collisions per second between the reactants, so the rate will be faster.

A. is wrong. Pepper might make you sneeze, but it won't make the reaction go any faster.

B is wrong. Removing heat will cause the molecules to slow down, so fewer of them will have energy to get over the activation energy barrier.

D. is wrong. If a reactant has a small surface area, fewer of the other reactant molecules will be able to collide with it, so the reaction will slow down.

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Calculate the empirical formula the compound with the following percent composition: 27.59%C 1.15%H 16.09%N 55.17%O
jeyben [28]

Answer: C2HNO3

Explanation: C = 27.59/12.011 = 2.297

H = 1.15/1.008 = 1.1409

N = 16.09/14.007 = 1.1487

O = 55.17/15.999 = 3.4483

Divide by smallest result:

C = 2

H=1

N=1

O = 3

Empirical formula = C2HNO3

8 0
3 years ago
.....................?
liraira [26]

Answer:

Look at the periodic table of elements

Explanation:

Group 1 is the most reactive and to the right

Group 18 is least reactive and all the way to the left. The rest are in between. The groups go vertical.

You'd be able to solve with this information youre welcome

4 0
2 years ago
a beer's law plot was generated and the trendline had a slope of 137.2 l/mol. the absorbance of the unknown phosphate sample was
Lorico [155]

The phosphate concentration of the unknown sample is <u>0.002 M</u>

<u />

Beer's law, the quantity of power absorbed or transmitted by using a solution is proportional to the solution's molar absorptivity and the awareness of the solute. In easy terms, a greater focused answer absorbs greater light than a more dilute solution does.

C = εa/b

  =  0.285 / 137.2

   =<u> 0.002 M</u>

A sequence of fashionable solutions containing a purple dye was made by diluting an inventory answer and then measuring the percent transmittance of every answer at 505 nm (greenish blue). This wavelength became decided on with the aid of examining its absorption spectrum.

Lambert's law of absorption states that equal elements inside the equal absorbing medium soak up identical fractions of the mild that enters them. If in traversing a path of duration dx the intensity is decreased.

Learn more about beer's law here:-brainly.com/question/18591932

#SPJ4

7 0
10 months ago
The analysis of a hydrocarbon revealed that it was 85.7% C and 14.3% H by mass. When 1.77 g of the gas was stored in a 1.500-L f
gtnhenbr [62]

Answer:

The formula of hydrocarbon = C_3H_6

Explanation:

Moles =\frac {Given\ mass}{Molar\ mass}

% of C = 85.7

Molar mass of C = 12.0107 g/mol

% moles of C = 85.7 / 12.0107 = 7.14

% of H = 14.3

Molar mass of H = 1.00784 g/mol

% moles of H = 14.3 / 1.00784 = 14.19

Taking the simplest ratio for C and H as:

7.14 : 14.19 = 1 : 2

The empirical formula is = CH_2

Also, Given that:

Pressure = 508 Torr

Temperature = 17 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T = (17 + 273.15) K = 290.15 K  

Volume = 1.500 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 62.3637 L.torr/K.mol

Applying the equation as:

508 Torr × 1.500 L = n × 62.3637 L.torr/K.mol × 290.15 K  

⇒n = 0.0421 moles

Given that :  

Amount  = 1.77 g

Molar mass = ?

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.0421\ moles= \frac{1.77\ g}{Molar\ mass}

Molar mass of the hydrocarbon = 42.04 g/mol

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 1×12 + 2×1= 14 g/mol

Molar mass = 42.04 g/mol

So,  

Molecular mass = n × Empirical mass

42.04 = n × 14

⇒ n = 3

<u>The formula of hydrocarbon = C_3H_6</u>

5 0
2 years ago
Francium is the most reactive element in Group 1.
natali 33 [55]

Answer:

Francium is hypothesized to be the most reactive metal, but so little of it exists or can be synthesized, and the longest half-life of its most abundant isotope is 22.00 minutes, so that its reactivity cannot be determined experimentally.

Explanation:

Francium is an alkali metal in group 1/IA. All alkali metals have one valence electron. As you go down the group, the number of electron energy levels increases – lithium has two, sodium has three, etc..., as indicated by the period number. The result is that the outermost electron gets further from the nucleus. The attraction from the positive nucleus to the negative electron is less. This makes it easier to remove the electron and makes the atom more reactive.

Experimentally speaking, cesium (caesium) is the most reactive metal.

6 0
3 years ago
Read 2 more answers
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