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3 years ago

Which best summarizes a concept related to the work-energy theorem?

Physics

2 answers:

Sholpan [36]3 years ago

5 0

the answer is A.) When work is positive, the environment does work on an object.

rusak2 [61]3 years ago

4 0

The concept of work-energy theorem has become much of a fundamental principle in the field of physics, mechanics, and engineering. In addition, this theory primarily states that the change of kinetic energy of the system is equal to the sum of the work done that is acted by all forces on the object.

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The principal limitation of wind power is unpredictability. Please select the best answer from the choices provided

Lady_Fox [76]

<span>The correct answer is A: True. Although the ability to forecast weather has increased over the years, the ability to predict when and how much wind will occur at any given time and place is difficult. Weather conditions are subject to constant change and while some areas are known to have more wind than others, there is no guarantee about how much wind there will be as weather patterns vary in consistency.</span>

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4 years ago

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A uniform bar has two small balls glued to its ends. The bar is 2.00 m long and has mass 4.00 kg, while the balls each have mass

Talja [164]

Answer:

a)1.93 kg-m^2

b) 1.45 kg-m^2

c) = 0

d) 1.15 kg-m^2

Explanation:

mass of the bar M = 4 kg

length of the bar = 2 m

mass of balls m1= m2= 0.3 kg

moment of inertia of bar $I= \frac{ML^2}{12}$

about an axis perpendicular to the bar through its center.

a) MOI of bar + 2×m×(L/2)^2

$I= \frac{ML^2}{12}$ + $2m\frac{L}{2}^2$

now putting the values of m, M and L as above and solving we get

I= 1.93 kg-m^2

b) perpendicular to the bar through one of the balls

$I=M\frac{L^2}{3} +mL^2$

$I=4\frac{2^2}{3} +0.3\times4^2$ = 1.45 kg-m^2

c) parallel to the bar through both balls

zero as the no mass distribution along the parallel to the bar through both balls.

d) parallel to the bar and 0.500 m from it.

I= $(M+2m_1)\frac{1}{2}^2$

putting values and solving we get

1.15 kg-m^2

4 0

4 years ago

He drives 150 meters in 18 seconds. Assuming constant speed, what is his speed in meters per second?

ira [324]

Answer:

Explanation:

Givens

d = 150 meters

t = 18 seconds

r (rate) = ?

Formula

r = d/t

Solution

r = 150/18

r = 8.33 m/s

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3 years ago

An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. W

Marat540 [252]

Explanation:

Below is an attachment containing the solution.

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4 years ago

Pls guys what is displacement

KengaRu [80]

Answer:

Displacement is the shortest distance from your initial position to your final position. Therefore, displacement is a measurement of distance and not an "end-point."

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3 years ago

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