All categories

4 years ago

How does a virus make it into a cell and what happens to it as it tries to get to its target “The Nucleus”?

1 answer:

4 0

Once the virus gets into the host's body, it enters the nearest cell.Once it gets to the nucleus it turns that cell into a virus-production cell and once the immune system detects those viruses it takes action.

You might be interested in

What is the equation for finding the acceleration of an object moving in a straight line?

kiruha [24]

Acceleration can be found using one of the following suvat equations:

$v=u+at\\s=ut+\frac{1}{2}at^2\\s=vt-\frac{1}{2}at^2\\v^2-u^2=2as$

Explanation:

The acceleration of an object is defined as the rate of change of velocity of the object:

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time taken for the velocity to change from u to t

There are several equations used to find the acceleration of an object moving in a straight line (they are usually called suvat equation). Depending on which quantities are given in the problem, you can use one of the following equations:

$v=u+at\\s=ut+\frac{1}{2}at^2\\s=vt-\frac{1}{2}at^2\\v^2-u^2=2as$

where

$a$ is the acceleration

$s$ is the distance covered

$t$ is the time

$u$ is the initial velocity

$v$ is the final velocity

Learn more about acceleration and suvat equations:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

4 0

4 years ago

According to newton’s first law, when the net force acting on an object is zero, the object must _____.

zysi [14]

Remain at rest.

Hope this helps you.

5 0

3 years ago

Suppose astronomers built a 20-meter telescope. How much greater would its light-collecting area be than that of the 10-meter Ke

nirvana33 [79]

Answer:

4 times greater

Explanation:

Step 1: Calculate light-collecting area of a 20-meter telescope (A₁) by using area of a circle.

Area of circle = π*r² = $\frac{\pi d^{2}}{4}$

Where d is the diameter of the circle = 20-m

$A_{1} = \frac{\pi d^{2}}{4}$

$A_{1} = \frac{\pi (20^{2})}{4}$

A₁ = 314.2 m²

Step 2: Calculate light-collecting area of a 10-meter Keck telescope (A₂)

$A_{2} = \frac{\pi d^{2}}{4}$

Where d is the diameter of the circle = 10-m

$A_{2} = \frac{\pi (10^{2})}{4}$

A₂ = 78.55 m²

Step 3: divide A₁ by A₂

$= \frac{314.2 m^2}{78.55 m^2}$

= 4

Therefor, the 20-meter telescope light-collecting area would be 4 times greater than that of the 10-meter Keck telescope.

5 0

4 years ago

If the space station is 190 m in diameter, what angular velocity would produce an "artificial gravity" of 9.80 m/s2 at the rim?

ozzi

Answer:

The angular velocity produced is 0.321 rad/s.

Explanation:

Given :

Diameter of space station , D = 190 m.

Therefore, radius , $R=\dfrac{D}{2}=\dfrac{190}{2}=95\ m.$

Also, acceleration , $a=9.8\ m/s^2.$

We know, angular velocity , $\omega=\sqrt \dfrac{a}{R}$ .

Putting value of g and R in above equation.

We get ,

$\omega=\sqrt \dfrac{9.8\ m/s^2}{95\ m}$

$\omega=0.321\ rad/s.$

Hence, this is the required solution.

6 0

4 years ago

A person of mass m measures their weight with a scale. How does the person’s weight measurement at the equator, WEQ, compare wit

lakkis [162]

Answer:

Weight measurement at poles will be slightly more than at equator.

Explanation:

Firstly earth bulges at equator. This makes the body far from earth center at equator than poles. Secondly, the surface centrifugal forces of earth due to rotation also plays vital role in disturbing the gravity value. The centrifugal forces cancel the effect of gravity more at equator than at poles.These factors combine to create difference of about 0.5% in gravity values at pole and equator.

gravity at pole=9.832 m/s^2

gravity at equator=9.780 m/s^2

5 0

3 years ago