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denis-greek [22]
3 years ago
9

A 4 kg block has a coefficient of friction of 0.3 between itself and the surface

Physics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

C - 11.76 N (Newtons)

Explanation:

2 steps are needed,

First find the Force being applied by the box on the surface.

F = M(a) [Force equals: mass X Acceleration (of gravity)]

You get 39.2 N of Force.

Plug in the remaining values into the equation for Frictional Force

F(f) = μ(F) [Coefficient of Friction X Force applied by the Box]

So

F(f) = 0.3(39.2) = 11.76 N (of Frictional Force)

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irga5000 [103]

Answer:

compounds C and D

Explanation:

I believe this is correct

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Jane does 5 joules of work when she closes her bedroom window. She applies a force of 6 newtons to do the job. How far does she
insens350 [35]

<u>Statement</u><u>:</u>

Jane does 5 joules of work when she closes her bedroom window. She applies a force of 6 newtons to do the job.

<u>To </u><u>find </u><u>out:</u>

The displacement of the window when she pulled it.

<u>Solution</u><u>:</u>

  • Work done (W) = 5 J
  • Force (F) = 6 N
  • Let the displacement of the window be s.
  • We know, the formula of work done, i.e., W = Fs
  • Putting the values in the above formula, we get
  • 5 J = 6 N × s
  • or, s = (5 ÷ 6) m
  • or, s = 0.83 m

<u>Answer</u><u>:</u>

She pulls the window by 0.83 m.

Hope you could understand.

If you have any query, feel free to ask.

4 0
3 years ago
An insulator:
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<span>An insulator resists conduction of electrons.</span>
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4 years ago
If the real gi tract is 9 meters long, the model you created is what fraction of the real one
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7 0
4 years ago
You stand 17.5 m from a wall holding a softball. You throw the softball at the wall at an angle of 30.5 ∘ from the ground with a
emmainna [20.7K]

Answer: h = 20.92 m

Explanation: By using the law of conservation of energy, the kinetic energy of the ball equals it potential energy.

Kinetic energy =mv^2/2

Potential energy = mgh

Where m = mass of the object, v = velocity of object = 23.5 m/s

g = acceleration due gravity = 9.8 m/s^2

mv^2/2 = mgh

m cancels out each other on both sides , hence we have that

v^2 = 2gh.

We want the ball to move towards the wall (horizontal motion), hence we need the horizontal component of the velocity since the velocity is inclined at an angle of 30.5 to the ground (horizontal).

Hence v = 23.5 × cos 30.5, v = 20.248 m/s

Recall that v^2 = 2gh

(20.248)^2 = 2×9.8×h

409.98 = 19.6 h

h = 409.98/ 19.6

h = 20.92 m

7 0
3 years ago
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