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alisha [4.7K]
3 years ago
9

A bullet is shot from a rifle with a speed of 3,015 feet per second. Assuming the billet moves at a constant velocity what is th

e time rescuers die the biller to strike a target 4,146 meters away
Physics
1 answer:
VMariaS [17]3 years ago
3 0

Answer:

Explanation:

Given

final speed v = 3015ft/s

initial speed = 0m/s

Distance S = 4146m/s

Required

Time

Using the equation of motion to get the time;

S = (v+u)/2 * t

since 1m = 3.28084ft'

4146m = 3.28084 * 4146 = 13,602.36264feet

13,602.36264 = 3015+0/2 * t

13,602.36264 = 1,507.5t

t = 13,602.36264/ 1,507.5

t = 9.023 secs

Hence it will take 9.023 seconds the rescuer die the biller to strike a target

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A projectile is launched horizontally from a 20-m tall edifice with a vox of 25 m/s. How long will it take for the projectile to
NISA [10]

Answer:

a) First let's analyze the vertical problem:

When the projectile is on the air, the only vertical force acting on it is the gravitational force, then the acceleration of the projectile is the gravitational acceleration, and we can write this as:

a(t) = -9.8m/s^2

To get the vertical velocity we need to integrate over time to get:

v(t) = (-9.8m/s^2)*t + v0

where v0 is the initial vertical velocity because the object is thrown horizontally, we do not have any initial vertical velocity, then v0 = 0m/s

v(t) = (-9.8m/s^2)*t

To get the vertical position equation we need to integrate over time again, to get:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + p0

where p0 is the initial position, in this case is the height of the edifice, 20m

then:

p(t) = (-4.9m/s^2)*t^2+ 20m

The projectile will hit the ground when p(t) = 0m, then we need to solve:

(-4.9m/s^2)*t^2+ 20m = 0m

20m = (4.9m/s^2)*t^2

√(20m/ (4.9m/s^2)) = t = 2.02 seconds

The correct option is a.

b) The range will be the total horizontal distance traveled by the projectile, as we do not have any horizontal force, we know that the horizontal velocity is 25 m/s constant.

Now we can use the relationship:

distance = speed*time

We know that the projectile travels for 2.02 seconds, then the total distance that it travels is:

distance = 2.02s*25m/s = 50.5m

Here the correct option is a.

c) Again, the horizontal velocity never changes, is 25m/s constantly, then here the correct option is option b. 25m/s

d) Here we need to evaluate the velocity equation in t = 2.02 seconds, this is the velocity of the projectile when it hits the ground.

v(2.02s) =  (-9.8m/s^2)*2.02s = -19.796 m/s

The velocity is negative because it goes down, and it matches with option d, so I suppose that the correct option here is option d (because the sign depends on how you think the problem)

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3 years ago
A 783kg elevator rises straight up 164 meters. What is the potential energy of the elevator?
Vilka [71]

Answer:

potential \: energy = mgh \\ m = 783 \\ g = 10 \\ h = 164 \\ pe = 783 \times 10 \times 164 \\ =  7830 \times 164 \\  = 1284120 \: joule \\ thank \: you

8 0
2 years ago
Read 2 more answers
3.00Kg toy falls from a height of 1.00m. What is the kinetic energy just before the ground?
ivanzaharov [21]

Answer:K E = 29.4 J

Explanation:

7 0
3 years ago
A 265 g mass attached to a horizontal spring oscillates at a frequency of 3.40 Hz . At t =0s, the mass is at x= 6.20 cm and has
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Answer:

The phase constant is 7.25 degree  

Explanation:

given data

mass = 265 g

frequency = 3.40 Hz

time t = 0 s

x = 6.20 cm

vx = - 35.0 cm/s

solution

as phase constant is express as

y = A cosФ ..............1

here A is amplitude that is = \sqrt{(\frac{v_x}{\omega })^2+y^2 }  = \sqrt{(\frac{35}{2\times \pi  \times y})^2+6.2^2 }  =  6.25 cm

put value in equation 1

6.20 = 6.25 cosФ

cosФ  = 0.992

Ф = 7.25 degree  

so the phase constant is 7.25 degree  

5 0
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Drupady [299]
The answer is 1,600 J.

A work (W) can be expressed as a product of a force (F) and a distance (d):
W = F · d<span>

We have:
W = ?
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W = 20 kg*m/s² * 80 m
W = 20 * 80 kg*m/s² * m
W = 1600 kg*m²/s²
W = 1600 J
8 0
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