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vlabodo [156]
3 years ago
14

A train is going on a journey. First it travels east for 50 kilometers then it turns north and travels for 22 kilometers. Next i

t goes west for 50 kilometers. Finally, it travels south for a certain number of kilometers. At the end of its journey it is original location. How many kilometers did it travel in the southward directions?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
8 0

Answer:

Abha

Step-by-step explanation:nsma

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X+3y=3<br> 2x-4y=6<br><br> solve the equations
Gelneren [198K]
Subtract the second equation from double the first equation:

2x+6y-2x-(-4y)=0

10y=0

Therefore, y=0.  Substituting this into the first equation, we see that:

x+3(0)=3

x=3

Therefore, x=3.  The solution to this system is x=3, y=0, or (3, 0).
4 0
3 years ago
Read 2 more answers
(c³d)a(cd⁷)a<br>Simplify <br>​
Veseljchak [2.6K]

Answer:

= c^4 d^8 a^2

Step-by-step explanation:

Apply exponent rule: aa= a^2

= c^3 da^2 cd^7

= c^4 da^2 d^7

= c^4 d^8 a^2

5 0
3 years ago
A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents di
cupoosta [38]

Answer:

The probability value is almost equal to 0. Implying that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of decedents who died in the three-month period following their birthdays.

A random sample of 747 obituaries published recently in Salt Lake City newspapers revealed that 344 (or 46%) of the decedents died in the three-month period following their birthdays (123).

The probability (p) of anyone dying in any quarter if people die randomly during the year is simply 0.25.

The random variable <em>X</em> follows a Binomial distribution with parameters n = 747 and p = 0.25.

But the sample selected is too large and the probability of success is small.

So a Normal approximation to binomial can be applied to approximate the distribution of <em>p</em> if the following conditions are satisfied:

  1. np ≥ 10
  2. n(1 - p) ≥ 10

Check the conditions as follows:

 np=747\times 0.25=186.75>10\\n(1-p)=747\times (1-0.46)=560.25>10

Thus, a Normal approximation to binomial can be applied.

So,  p\sim N(\hat p,\ \frac{\hat p(1-\hat p)}{n}).

Compute the probability that 46% or more would die in that particular interval if deaths occurred randomly throughout the year as follows:

P (p\geq 0.46)=P(\frac{p-\hat p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}}>\frac{0.46-0.25}{\sqrt{\frac{0.25(1-0.25)}{747}}})

                   =P(Z>13.25)\\=1-P(Z

 *Use a <em>z</em> table for the probability.

The probability value is almost equal to 0. This probability is very low indicating that the proportion of people dying  in that particular interval if deaths occurred randomly throughout the year is unusual.

3 0
3 years ago
What is the slope of the line describe by the equation y=-6x-2
Alexandra [31]

Answer:

The slope(M) is -6

Step-by-step explanation:

:)

8 0
3 years ago
What is the product of 1 1/2 and −1 1/4 ? Enter your answer as a mixed number, in simplified form, in the box.
ioda
11/2 * -11/4  = (11*-11) / 2*4  =   -121 / 8

= -15 1/8 answer

-2 1/4 * -4 1/2
= -9/4 *  -9/2
=  81/8
= 10 1/8  answer
4 0
3 years ago
Read 2 more answers
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