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GREYUIT [131]
3 years ago
13

What is 14x65?. Whoever answers with detail will be marked brainliest. Plz don't type random. I will give 29 points to solvers!

Mathematics
2 answers:
Gwar [14]3 years ago
8 0
The answer is 910. 

14
x65
 
if you set it up shown above you do 5 times 4 then five times 1. then underneath that do 6 times four and then six times 1. then you add those two numbers. sorry if this sounds confusing its hard to explain and easier to explain when actually doing the problem by hand 
nekit [7.7K]3 years ago
7 0
The answer for your question is 910
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Jimmy took out a loan for $5,600 to pay for a home repair the bank offered an interest rate of 4.75 % how much interest would sh
Serjik [45]

Answer:

$698

Step-by-step explanation:

Given that :

Principal = $5600

Rate = 4.75%

Time = 3 years

Simple interest = principal * rate * time

Simple interest = $5600 * 0.0475 * 3

simple interest = $798

7 0
2 years ago
What is 2x(x+5)=4 using the quadratic formula
antoniya [11.8K]
X= \frac{-5(+/=) \sqrt{33} }{2}
Or it would be approximately: x≈ 0.37228132, -5.37228132
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4 0
3 years ago
7b<br> Evaluate when b= -1<br> b-3
tiny-mole [99]

Answer:

b-3

-1-3

-4

is the correct answer

5 0
3 years ago
Find the radius y of circle C, given that x = 12 and z = y + 8.<br> PLEASEEE HELP ME
myrzilka [38]
I think the answer is 3 :))
6 0
3 years ago
G with the definition of covariance, prove cov[(ay − b),(cy − d)] = accov(x, y ), where x, y are random variables and a, b, c, d
____ [38]

By definition of covariance,


\mathrm{Cov}(X,Y)=\mathbb E[(X-\mathbb E[X])(Y-\mathbb E[Y])]


\mathrm{Cov}(X,Y)=\mathbb E[XY-\mathbb E[X]Y-X\mathbb E[Y]+\mathbb E[X]\mathbb E[Y]]=\mathbb E[XY]-\mathbb E[X]\mathbb E[Y]


We have


\mathbb E[(aX-b)(cY-d)]=\mathbb E[acXY-adX-bcY+bd]

=ac\mathbb E[XY]-ad\mathbb E[X]-bc\mathbb E[Y]+bd


\mathbb E[aX-b]=a\mathbb E[X]-b


\mathbb E[cY-d]=c\mathbb E[Y]-d


\mathbb E[aX-b]\mathbb E[cY-d]=ac\mathbb E[X]\mathbb E[Y]-ad\mathbb E[X]-bc\mathbb E[Y]+bd


Putting everything together, we find the covariance reduces to


\mathrm{Cov}(aX-b,cY-d)=ac(\mathbb E[XY]-\mathbb E[X]\mathbb E[Y])=ac\mathrm{Cov}(X,Y)


as desired.

5 0
3 years ago
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