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LenaWriter [7]
3 years ago
10

a basketball player looks directly at the rim that is 10 feet high. the angle of elevation from her eye level, which is 6feet ab

ove the ground, to the rim is 25 degrees. to the nearest foot, how far away from the rim is she standing
Mathematics
1 answer:
Aneli [31]3 years ago
6 0
Her horizontal distance to the rim satisfies the ratio
  (10 ft -6 ft)/distance = tan(25°)
so the distance is
  distance = (4 ft)/tan(25°) ≈ 9 ft
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Nutka1998 [239]

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In circle J with mZHLK = 18, find the mZHJK.
zysi [14]

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<em><u>In a circle</u></em>, <em>the measure of the inscribed angle equal half the measure of the central angle subtended by the same arc</em>

In circle J

∵ J is the center of the circle

∵ H and K lie on the circle

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∵ L lies on the circle

∴ ∠HLK is an inscribed angle subtended by arc HK

→ By using the rule above

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→ Multiply both sides by 2

∴ 36 = m∠HJK

∴ The measure of angle HJK is 36°

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3 years ago
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