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3 years ago

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The sum of two numbers is 52 . The smaller number is 16 less than the larger number.What are the numbers?

2 answers:

eimsori [14]3 years ago

4 0

Answer:

This question is not as hard as it seems.

Let the first number = x.

The other number will be x - 16.

The sum of both the number is 52.

So, x+x-16 = 52

Which would simplify to 2x -16 = 52.

When I add 16 to both sides, it would give me 2x = 68.

Then, divide both sides by 2.

This leaves us with x = 34.

Since we have x, now x-16 would be 34-16 = 18.

The two numbers are 34 and 18, this answer is correct because both of them add up to give me 52.

HOPE THIS HELPS!

vodka [1.7K]3 years ago

4 0

Question

The sum of two numbers is 52 . The smaller number is 16 less than the larger number.What are the numbers?

Answer:

18 and 34

Step-by-step explanation:

[(52 - 16) : 2] + 16 =

(36 : 2) + 16 =

18 + 16 =

34

-----------------------

Check

34 - 18 = 16

34 + 18 = 52

the answer is good

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2 years ago

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3 years ago

The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo

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Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY = $\sqrt{x^2+y^2}$

Therefore, the length between points AB is

length AB = $\sqrt{(-4 - (-2))^2+(-1-3)^2}$

= $\sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2} = \sqrt{20}$ = 4.472 units

Similarly, length BC is given by

Length BC = $\sqrt{(-4)^2+1^2} = \sqrt{17}$ = 4.123 units

Length CD = $\sqrt{(-2)^2+5^2} = \sqrt{29}$ = 5.385 units

Length DA = $\sqrt{(8)^2+(-2)^2} = \sqrt{68}$ = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A = $\sqrt{(7)^2+(0)^2} = \sqrt{49}$ =7 units

The perimeter of polygon ABCD'

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= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

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$S_{\bigtriangleup}$ = $(\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|$

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A(-4,-1)

B(-2,3)

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Area of polygon ABCD' = 19.5 units².

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2 years ago

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Answer:

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Step-by-step explanation:

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