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Vlada [557]
3 years ago
12

the saginaw bay tides vary between 2 feet and 8 feet. the tide is at its lowest point when time (t) is 0 and completes a full cy

cle in 16 hours. what is the amplitude, period, and midline of a function that would model this periodic phenomenon?
Mathematics
2 answers:
FrozenT [24]3 years ago
6 0

Answer:

Amplitude = 3 feet

Period = 16 hours

Midline y = 5

Step-by-step explanation:

The saginaw bay tides vary between 2 feet and 8 feet that means amplitude of the wave function will be a=\frac{8-2}{2}=\frac{6}{2}=3feet

Now midline of the function will be y=\frac{8+2}{2}=5

As it has been given in the question that tide completes a full cycle in 16 hours that means period of the function formed will be 16 hours.

                                         

Mrrafil [7]3 years ago
3 0
I just took the test the correct answer is:
Amplitude = 3 feet; 3 period = 16 hours; midline: y = 5.
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Step-by-step explanation:

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Number of values in data class 1: n1=2

2. Data class 2: 880-899

Midpoint 2: M2=(880+899)/2=1,779/2→M2=889.5

Number of values in data class 2: n2=5

3. Data class 3: 900-919

Midpoint 3: M3=(900+919)/2=1,819/2→M3=909.5

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4. Data class 4: 920-939

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Number of values in data class 5: n5=1


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Mean=(M1*n1+M2*n2+M3*n3+M4*n4+M5*n5)/(n1+n2+n3+n4+n5)

Mean=(869.5*2+889.5*5+909.5*10+929.5*6+949.5*1)/(2+5+10+6+1)

Mean=(1,739+4,447.5+9,095+5,577+949.5)/(24)

Mean=(21,808)/(24)

Mean=908.6666666

Rounding to one decimal place:

Mean=908.7

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