Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Step-by-step explanation:
1) the domain is from -3 to 5 D [-3,5]
the range is from -5 to -2. R [-5,-2]
2)the domain is from -3 to 6 but not including 6 D [-3,6)
the range is from -5 but not including -5 to 2. R (-5,2]
Answer:
4
step by step:
b-9=4
Answer:
Radius = 4.51
Step-by-step explanation: