A) 1.05 N
The power dissipated in the circuit can be written as the product between the pulling force and the speed of the wire:
where
P = 4.20 W is the power
F is the magnitude of the pulling force
v = 4.0 m/s is the speed of the wire
Solving the equation for F, we find
B) 3.03 T
The electromotive force induced in the circuit is:
(1)
where
B is the strength of the magnetic field
v = 4.0 m/s is the speed of the wire
L = 10.0 cm = 0.10 m is the length of the wire
We also know that the power dissipated is
(2)
where
is the resistance of the wire
Subsituting (1) into (2), we get
And solving it for B, we find the strength of the magnetic field:
Answer:
Runner A will be 0.05 km from the flagpole, and runner B will be 0.07 km from the flagpole
Explanation:
We can find when their paths will cross as follows:
Where:
is the final position
is the initial position
v₀ is the initial speed
t is the time
a is the acceleration = 0 (since they are running with a constant velocity)
When their paths cross we have:
Now we can find the final distance of each runner.
Therefore, runner A will be 0.05 km from the flagpole, and runner B will be 0.07 km from the flagpole.
I hope it helps you!
Answer:
• Pressure inside liquids are due to the random movement of the liquid molecules and the weight of the liquid. The pressure inside solids occurs only due to the weight of the solid.
• The liquid pressure acts on the sides of the liquid as well as the bottom. The pressure due to solids only appears at the bottom of the solid.
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