To answer the question above,
First, let's determine the speed of sound under the water.
S
peed of sound in water at 20oC = 1482m/s
<span>So λ = v/f = 1482m/s/(100kHz) I'm assuming your frequency is 100kHz </span>
<span>So λ would be = 0.0148m
I hope my answer helped you.</span>
Answer:
675m
Explanation:
Given parameters:
Initial velocity = 0m/s
Acceleration = 6m/s²
Time = 15s
Unknown:
Distance traveled by the body = ?
Solution:
To solve this problem; we use the expression;
S = ut +
at²
Where u is the initial velocity
t is the time
a is the temperature
Insert the parameters and solve;
S = 0 x 15 +
x 6 x 15²
S = 675m
Heat rises, and it is warmer at the equator, so I think warm air would rise at the equator and move towards the cooler poles.
Answer:
<h2>3.36J</h2>
Explanation:
Step one:
given data
mass m= 1.3kg
distance moved s= 2.8m
opposing frictional force= 0.34N
assume g= 9.81m/s^2
we know that work done= force *distance moved
1. work done to push the book= 1.55*2.8=4.34J
2. Work against friction = force of friction x distance
= 0.34*2.8=0.952J
Step two:
the work done on the book is the net work, which is
Network done= work done to push the book- Work against friction
Network done= 4.32-0.952=3.36J
<u>Therefore the work of the 1.55N 3.36J</u>