Question

Multiply the following numbers, using scientific notation and the correct amount of significant digits. 1.003 m⋅3.09 =

Answer 1

Explanation:

In this question, we have to write the product of two numbers using scientific notation and the correct amount of significant digits.

First number, n₁ = 1.003

Second number, n₂ = 3.09

The product of above numbers is given by P as :

P = n₁ × n₂

P = 1.003 × 3.09

P = 3.09927

Here, the 4th significant figure is 9. It is greater than 5 so it will added to the previous digit.

or

P = 3.1

Scientific figures are written in the form as :

$a\times 10^b$

Where

a = any real number

b = integer

Hence, this is the required solution.

Answer 2

The correct answer to the question is: 3.10

CALCULATION:

As per the question, the two numbers are given as 1.003 and 3.09.

We are asked to multiply these two numbers.

The multiplication result of the two numbers = 1.003 × 3.09

= 3.09927.

We have to rewrite this result in terms of rule of significant digits.

The total number of significant digits of first number is 4.

The total number of significant digits of second number is 3.

Hence, the minimum number of significant digits is 3.

As per the significant rules for multiplication, the final result will follow the minimum number of significant digits.

Hence, the final answer should contain only three significant digits.

The multiplication result is rounded off after three significant digits.

The fourth significant digit is 9 which is to be rounded off.

As, it is greater than 5, so 1 will be added to the preceding digit.

Hence, the multipled result = 3.10

Hence, the correct answer of this question is 3.10