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kobusy [5.1K]
3 years ago
14

Solomon is 9 years old younger than his brother.His brother is 21.How is brother?

Mathematics
1 answer:
Alla [95]3 years ago
8 0

Answer:

/

''''''''''''''''

Step-by-step explanation:


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Montell is 30 years younger than his mother. in 5 years, montell age will be 1-3 of his mother’s age. find montell mother’s age
Liono4ka [1.6K]
So this can be solve by establish two equation:
let x be age of montell
y be tha age of her mom
for the first equation (<span>Montell is 30 years)</span>:
x = y - 30
second equation ( in 5 years )

x + 5 = ( y + 5 ) ( 1/3)
solving the equation simultaneously

x = 10 years old
y = 40 years old
8 0
3 years ago
How do i solve this if i dont pass my math i lose my phone for a week got till tomorrow
Flura [38]
Do you need an explanation of the work shown? The distance can be found by multiplying the rate by the time. as long as you know two of three parts, you can find the missing value. There is no problem shown in the picture?
6 0
3 years ago
Please help fasttt!!
gogolik [260]

Answer:

then u help me

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
If f(x)=x^3-x+2, then (f^-1)'(2)
yawa3891 [41]

Note that f(x) as given is <em>not</em> invertible. By definition of inverse function,

f\left(f^{-1}(x)\right) = x

\implies f^{-1}(x)^3 - f^{-1}(x) + 2 = x

which is a cubic polynomial in f^{-1}(x) with three distinct roots, so we could have three possible inverses, each valid over a subset of the domain of f(x).

Choose one of these inverses by restricting the domain of f(x) accordingly. Since a polynomial is monotonic between its extrema, we can determine where f(x) has its critical/turning points, then split the real line at these points.

f'(x) = 3x² - 1 = 0   ⇒   x = ±1/√3

So, we have three subsets over which f(x) can be considered invertible.

• (-∞, -1/√3)

• (-1/√3, 1/√3)

• (1/√3, ∞)

By the inverse function theorem,

\left(f^{-1}\right)'(b) = \dfrac1{f'(a)}

where f(a) = b.

Solve f(x) = 2 for x :

x³ - x + 2 = 2

x³ - x = 0

x (x² - 1) = 0

x (x - 1) (x + 1) = 0

x = 0   or   x = 1   or   x = -1

Then \left(f^{-1}\right)'(2) can be one of

• 1/f'(-1) = 1/2, if we restrict to (-∞, -1/√3);

• 1/f'(0) = -1, if we restrict to (-1/√3, 1/√3); or

• 1/f'(1) = 1/2, if we restrict to (1/√3, ∞)

6 0
2 years ago
FIND om if LO bisects
disa [49]
First you use Pythagorean theorem to find LO is square root of 194(13^2 + 5^2)=13.9. Then use the same method to find OM (194+13^2=363, square root of 363 is 19.1) and get that OM is 19.1
7 0
3 years ago
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