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Serjik [45]
2 years ago
8

Hello"! Need Help!

Mathematics
1 answer:
stealth61 [152]2 years ago
4 0
<h3>⚠ANSWER⚠</h3>

<em><u>↪</u></em><em><u>Given 15 cot A = 8. Find sin A and sec A </u></em>

Hope this helps...☆

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F(x) = 2(x+3)2 -7<br><br><br> a= <br><br> h=<br><br> k=
vlabodo [156]

Answer:

Step-by-step explanation:

In vertex form, the equation is

y = a(x-h)^2 + k

So just read off the values!

6 0
3 years ago
What is (0.2 + -5) x (4.1) ?
nevsk [136]

Answer:

-19.68

Step-by-step explanation:

(0.2 + (-5) × (4.1)

-4.8 × (4.1)

-19.68

6 0
3 years ago
Read 2 more answers
Evaluate the expressions below for given values
sweet-ann [11.9K]
The answer to the question

8 0
3 years ago
What is the surface area of a box with the dimensions of length 4cm, width 3cm, and height 5cm? Only type the number - no units.
stich3 [128]

Answer:

heyy

Step-by-step explanation:

5 0
3 years ago
Please answer I’ll rate brainlyest
12345 [234]

Answer:

5P3*6C4=60*15=900

Step-by-step explanation:

5P3 refers to the permutations of 5 items taken 3 at a time. To evaluate this, we use factorials as follows;

5P3=\frac{5!}{(5-3)!}

The factorial of an integer n is evaluated as;

n!=n*(n-1)*(n-2)*(n-3).......3*2*1

Using this concept, the above expression can now be simplified as follows;

5P3=\frac{5!}{2!}=\frac{5*4*3*2!}{2!}=5*4*3=60

Therefore, the permutations of 5 items taken 3 at a time is 60.

The next expression, 6C4 refers to the combinations of 6 items taken 4 at a time. The simplification utilizes similar concepts of permutations since we shall be involving factorials;

6C4=\frac{6!}{4!(6-4)!}=\frac{6!}{4!*2!}=\frac{6*5*4!}{4!*2*1}=\frac{6*5}{2*1}=15

Therefore, the combinations of 6 items taken 4 at a time is 15.

The final step is to evaluate the product;

5P3*6C4=60*15=900

3 0
3 years ago
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