All categories

2 years ago

-3|2w|=-6 SOLVE THE EQUATION

Mathematics

1 answer:

ElenaW [278]2 years ago

3 0

Answer:

w=-1

Step-by-step explanation:

You might be interested in

2.5=25% is it true or false

Gnom [1K]

Answer: false

explanation;

6 0

2 years ago

Read 2 more answers

8) Factor each sum or difference of cubes completely. a. 8x3 + 27

ASHA 777 [7]

Answer:

$\large\boxed{(2x+3)(4x^2-6x+9)}$

Step-by-step explanation:

$8=2^3\\\\8x^3=2^3x^3=(2x)^3\\\\27=3^3\\\\8x^3+27=(2x)^3+3^3\qquad\text{use}\ a^3+b^3=(a+b)(a^2-ab+b^2)\\\\=(2x+3)\bigg((2x)^2-(2x)(3)+3^2\bigg)=(2x+3)(4x^2-6x+9)$

4 0

3 years ago

140% out of what gives 56

Verizon [17]

140 / 100 * X = 56

X = 56 * 100 / 140 = 5600 / 140 = 40

4 0

3 years ago

Read 2 more answers

A flying squirrel lives in a nest that is 9 meters high in a tree. To reach a fallen acorn that is 4 meters from the base of the

Luba_88 [7]

Answer:

Flying squirrel have to glide is for 9.8 meters approximately.

Step-by-step explanation:

Here we can use Pythagoras theorem.

Height is 9 , base is 4.

We need to find the hypotenuse measure.

So, let's use Pythagoras theorem $a^{2} +b^{2}= c^{2}$

Plug in a as 9 and b 4.

$9^{2} +4^{2}=c^{2}$

Simplify the left side of the equation

$81+16=c^{2}$

$97=c^{2}$

Take square root on both sides.

c=9.8 meters.

6 0

2 years ago

Use the standard norml distribution or the t-distribution to construct a 99% confidence interval for the population mean. Justif

dalvyx [7]

Answer:

E) we will use t- distribution because is un-known,n<30

the confidence interval is (0.0338,0.0392)

Step-by-step explanation:

Step:-1

Given sample size is n = 23<30 mortgage institutions

The mean interest rate 'x' = 0.0365

The standard deviation 'S' = 0.0046

the degree of freedom = n-1 = 23-1=22

99% of confidence intervals $t_{0.01} =2.82$ (from tabulated value).

$The mean value = 0.0365$

$x±t_{0.01} \frac{S}{\sqrt{n-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{23-1} }$

$0.0365±2.82 \frac{0.0046}{\sqrt{22} }$

$0.0365±2.82 \frac{0.0046}{4.690 }$

using calculator

$0.0365±0.00276$

Confidence interval is

$(0.0365-0.00276,0.0365+0.00276)$

$(0.0338,0.0392)$

the mean value is lies between in this confidence interval

(0.0338,0.0392).

Answer:-

using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.

4 0

2 years ago