Answer:
-2
Step-by-step explanation:
We can find the slope of a line given two points from
m = (y2-y1)/(x2-x1)
= (-2-4)/(1--2)
= (-6)/(1+2)
=-6/3
=-2
Class A: 6v + 8b = 202
Class B: 12v + 16b = 284
Solve using the elimination method:
since 6v and 12v are perfect for elimination, multiply the class A equation by 2 so that the van variable cancels out:
12v + 16b = 404
12v + 10b = 284
Then subtract the bottom equation from the top:
6b = 120
b = 20
Now you know that each bus can hold 20 students.
Just plug this into one of the original equations to solve for vans:
6v + 8(20) = 202
6v + 160 = 202
6v = 42
v=7
So then you know that each van can hold 7 students.
Check:
12 (7) + 10 (20) = 284
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<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>B</em><em>.</em><em>.</em>
Answer:
<h2>x = 2, y = 6 → (2, 6)</h2>
Step-by-step explanation:

