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Alchen [17]
3 years ago
13

√5•√80 Show your steps pls ty

Mathematics
1 answer:
kykrilka [37]3 years ago
8 0

Answer:

20

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

Given

\sqrt{5} × \sqrt{80}

= \sqrt{5(80)}

= \sqrt{400}

= 20

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Need help ASAP.<br> 50×50+60-105=?
Mandarinka [93]

Answer:

2,455

Step-by-step explanation:

Use PEMDAS to solve

First multiply 50x50, which is 2,500

50 x 50 + 60 - 105   becomes

2,500 + 60 - 105

Now to the addition or subtraction from left to right

2,560 - 105

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4 0
3 years ago
Read 2 more answers
X/3 +17 less than or equal to 15
Sliva [168]

x \leqslant  - 6

x/3+17is less than or equal to 15

x/3is less than or equal to 15-17

xis less than or equal to -6

5 0
3 years ago
2x^2 +5x+3/x^2+2x+1​
german

Answer:

\frac{2x+3}{x+1}

Step-by-step explanation:

2x² + 5x + 3 = (x + 1) (2x + 3)

x² + 2x + 1 = (x + 1) (x + 1)

(x + 1) cancels out because there is one in the denominator and the numerator, leaving you with the answer.

Hope this helps!

3 0
3 years ago
I don't- I don't know i need help
Vesnalui [34]

Answers:

Monthly gross pay =  $7650.68

Annual gross pay = $91808.16

Explanation:

To get the monthly gross pay, you double the semi-monthly gross pay. In other words, you multiply by 2.

Once you know how much you earn per month, you multiply that by 12 to get your annual pay.

The term "gross" in financial terms means the amount of money before taxes and other fees apply. The net pay is after taxes and other fees are deducted from your paycheck. This means the net pay is going to be smaller than the gross pay.

4 0
3 years ago
Can the following question be considered a statistical question and why or why not?
FinnZ [79.3K]

It could. If you turn it into an experiment. Let's say you take 100 students from each grade, and you ask them if they exercise. And then you wanna create a graph. And find out out of those students how many of them exercise and how many of them do not. Then turn it into a percent.

I hope this helps. If you have any further questions on this or any other questions just ask. I am here to help you, as needed.

7 0
3 years ago
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