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3 years ago

If g(x)=1/x were shifted 3 units to the left and 3 units up, what would the new equation be

Mathematics

1 answer:

emmainna [20.7K]3 years ago

4 0

Answer:

g(x) 1/3-4

Step-by-step explanation:

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What is the measure of the other acute angle ?

Vaselesa [24]

Answer:

$62^{o}$

Step-by-step explanation:

All the angles in a triangle add up to $180^{o}$

Every right angle triangle has a right angle in it which is $90^{o}$

So to find the remaining angle, you do $180^{o}$ - $90^{o}$ - $28^{o}$ = $62^{o}$

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2 years ago

NEED ANSWER IN LESS THAN 10 MINS!!

Naddik [55]

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3 years ago

Jasmin, Quinn, and Maddy are rock climbing. Jasmin is 42 ½ feet below Quinn. Maddy is 67 ¾ feet above Jasmin. What is Maddy's po

ladessa [460]

Answer:

$25\frac{1}{4}$ feet

Step-by-step explanation:

Given

$Maddy = 67\frac{3}{4}$ above Jasmin

$Jasmin = 42\frac{1}{2}$ below Quinn

Required

Determine Maddy's position relative to Quinn's

From the given parameter, one can easily deduce that Quinn is in between Maddy and Jasmin (See attachment)

Using the attachment as a point of reference;

$z = 67\frac{3}{4}$

$x = 42\frac{1}{2}$

The relationship between x, y and z is

$z = y + x$

Make y the subject of formula

$y = z - x$

Substitute the values of z and x

$y = 67\frac{3}{4} - 42\frac{1}{2}$

Convert to improper fractions

$y = \frac{271}{4} - \frac{85}{2}$

Take LCM

$y = \frac{271 - 170}{4}$

$y = \frac{101}{4}$

$y = 25\frac{1}{4}$

Hence; Maddy's position relative to Quinn's is  $25\frac{1}{4}$  feet

8 0

3 years ago

Write the situation for the relationship "y = 2x - 5."

kompoz [17]

Its letter b can u please help me in my question

3 0

3 years ago

Kite EFGH is inscribed in a rectangle where F and H are midpoints of parallel sides. The area of EFGH is 35 square units. What i

sasho [114]

*see attachment for the figure described

Answer:

5 units

Step-by-step explanation:

==>Given the figure attached below, let where FH and EG intercepted be K.

Since FH are midpoints of parallel lines, KE = KG = x.

Given that the area of the kite EFGH = 35 square units, and we know the length of one of the diagonals = HF = KF + KH = 2 + 5 = 7, we can solve for x using the formula for the area of a kite.

Area of kite = ½ × d1 × d2

Where d1 = KH = 7

d2 = EG = KE + KG = x + x = 2x

Area of kite EFGH = 35

THUS:

35 = ½ × 7 × 2x

35 = 1 × 7 × x

35 = 7x

Divide both sides by 7

35/7 = x

x = 5

4 0

3 years ago