Question

A line passes through points (-4, -19) and (-6, 4). what is the equation of the line written in slope-intercept form?

Answer 1

The equation of the line written in slope-intercept form is:

$y = mx + b$
Where m is the slope and b is the y-intercept.
You find the slope using the formula:

$m = \frac{yb - ya}{xb - xa}$
Where point A coordinates' are (-4,-19) and point B (-6, 4).

$m = \frac{4 + 19}{ - 6 + 4}$
$m = - \frac{23}{2}$
Now you find b (y-intercept) substituting in y=-23/2x+b the coordinates of point A or point B:
(I'll use point B coordinates')
y=-23/2x+b
4=-23/2×(-6)+b
4=46+b
b=-42
The equation of the line is y=-23/2x-42