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enyata [817]
3 years ago
15

What is the equation of a line that is parallel to the line with the equation y=2/3x+2 and passes threw the point 1,-1

Mathematics
1 answer:
Lilit [14]3 years ago
5 0

The equation of line parallel to given line is: y = \frac{2}{3}x-\frac{5}{3}

Step-by-step explanation:

Given equation of line is:

y = \frac{2}{3}x+2

As the line is in slope-intercept form, the co-efficient of x is the slope of the line

So,

m_1 =\frac{2}{3}

Let m2 be the slope of required line

As both the lines are parallel,

m_1 = m_2

So,

m_2 = \frac{2}{3}

The slope intercept form of line is:

y = mx+b

Putting the value of the slope

y = \frac{2}{3}x+b

To find the value of b, putting (1,-1) in the equation

-1 = \frac{2}{3}(1) +b\\-1 = \frac{2}{3} +b\\b = -1-\frac{2}{3}\\b = \frac{-3-2}{3}\\b = \frac{-5}{3}

Putting b=-5/3 in the equation

y = \frac{2}{3}x-\frac{5}{3}

Hence,

The equation of line parallel to given line is: y = \frac{2}{3}x-\frac{5}{3}

Keywords: Equation of line, slope

Learn more about equation of line at:

  • brainly.com/question/10703930
  • brainly.com/question/10772025

#LearnwithBrainly

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