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bazaltina [42]
3 years ago
6

Tyler took out a loan at a 14.7% APR, compounded monthly, to buy a boat,

Mathematics
2 answers:
Zanzabum3 years ago
7 0

Answer:

14.4%, compounded monthly

Step-by-step explanation:

APEX

Reptile [31]3 years ago
3 0

Answer: 14.4%

Step-by-step explanation:

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Help please, Which expression does not belong? Explain your reasoning.
ZanzabumX [31]

Answer:

My best answer is option number 4.

Step-by-step explanation:

Because the first 3 answers follow a specific pattern in addition and division, i.e. they only go up to 4 different numbers, whereas with the 4th option, that changes. Not only that, but if you look closely, the 4th option adds 6 to itself 5 times, that's the same as 6x5, which equals 30, so if you divide 30 by 5, its almost pointless seeing as how you already know it's gonna get you 6.

4 0
3 years ago
If EG = 59, and EF = 8x - 14, while FG = 4x + 1
lyudmila [28]

Answer:

x = 6

Step-by-step explanation:

EG = 59

EF = 8x - 14

FG = 4x + 1

to find the value of x

EF + FG = EG (same line)

8x - 14 + 4x + 1 = 59

12x -13 = 59

12x = 59 + 13

12x = 72

x = 72 ÷ 12

x = 6

You can even cross check for correct answer

EF + FG = EG

instead of x place the x's value we got

8x - 14 + 4x + 1 = 59

8 (6) - 14 + 4 (6) + 1 = 59

48 - 14 + 24 + 1 = 59

34 + 25 = 59

59 = 59

CROSS - CHECKED

4 0
2 years ago
Who can help me finish a course on edge ive done half of the course already its algebra !!
tester [92]

Sure, post the questions.

7 0
2 years ago
What is the area of a square with a side of 8x^7 y^3
sukhopar [10]
Area of a square with side s is \sf{s^2}

In your question, the side or s is: \sf{8x^7y^3}

And so the area of a square with that side length would be:

\sf{(8x^7y^3)^2}

And using this formula: \sf{(a^b)^c =a^{b\times c}}

We get that the area is:

\sf{(8x^7y^3)^2 = 8^2 x^{7\times 2} y^{3\times 2}}

And simplifying that we get the final answer as:

\huge{\boxed{\bf{Area=64x^{14}y^{6}}}}
4 0
3 years ago
A person weighing 170 lb burns 8.6 calories per minute while mowing a lawn. How many calories would be burned A person weighing
lord [1]

Answer:

4,644 calories

Step-by-step explanation:

The computation of the number of calories to be burned is shown below

r = rate = 8.6 cal/min

= 8.6 cal ÷ [(1 ÷ 60)hr]

= 516 cal/hr

Now

Calories consumed in 9 hours is

= (516 cal/hr) × (9 hrs)

= 4,644 calories

8 0
3 years ago
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