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3 years ago

WILL GIVE BRAINLIEST what is the range of this function?

Mathematics

2 answers:

Lyrx [107]3 years ago

5 0

Answer:

R: { -8,-3,5,7}

Step-by-step explanation:

The range is the output values

R: { -8,-3,5,7}

Fantom [35]3 years ago

5 0

Answer:range={-8,-3,5,7} option A

Step-by-step explanation:

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All even please! Show work please and thank you

MAXImum [283]

2. 12x 4. 16x + 8y 6. 11x

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4 years ago

What is the total area, in square feet, of the figure? (If possible please explain how you got your answer)

GalinKa [24]

Answer:

This is going to be really long so sorry in advance :)). So i split the shape into two (so straight down).This therefore allows me to calculate the areas of both rectangles and add them together - (to give total area)

Area of A x(x^2-6)

=x^3-6x

Area of B

=(2x^3-5x^2-12x+14) (5x-14)

10x^4-28x^3-25^3-70x^2-60x^2+168x+70x-196

simplified: 10x^4-53^3-130x^2+238x-196

so add both areas to give total are:

=(x^3-6x) +(10x^4-53x^3-130x^2+238x-196)

=10x^4-52x^3-130x^2+232x-196

Thats it hope it helps :)

Step-by-step explanation:

4 0

3 years ago

Question is show below.

WITCHER [35]

(1/4ab)^-2

Remove negative exponent by rewritten the equation as (4ab)^2

AUse Product rule to get:

4^2a^2b^2

Now raise 4 to the second power to get:

16a^2b^2

The last answer is correct.

7 0

3 years ago

3. Using the sample size of 800 and the proportion 0.47, calculate the margin of error associated with the estimate of the propo

salantis [7]

Answer:

$ME=1.96\sqrt{\frac{0.47 (1-0.47)}{800}}=0.0346$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Solution to the problem

We assume for this case a confidence level of 95%. In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by: