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My name is Ann [436]
3 years ago
6

Find the sixth term of the sequence 1/2,3/8,9/32...

Mathematics
2 answers:
geniusboy [140]3 years ago
6 0
It will be 33 since that's what the patterns like
maxonik [38]3 years ago
4 0
I think it would be 27/128. 75% of 1/2 is 3/8, so assuming the pattern is multiplying each fraction by 3/4, then 9/32 x 3/4 is 27/128. Hope this helped.
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The sum of 45% of a number and 55% of the same number is 200. what is the number?
Ymorist [56]

.45x+.55x=200
Combine like terms
1x=200
So x is 100

Or you can do 45%+55%=100%
And 100% of 200 is 200
8 0
3 years ago
Uses both multiplication and addition to find the result
krok68 [10]

Answer:

Where's the question or picture?


Step-by-step explanation:


8 0
3 years ago
25x -5 + 32 = (when x = 3)
Ugo [173]

Answer:

102

Step-by-step explanation:

25 x 3 - 5 + 32

75 - 5 + 32

70 + 32

=102

4 0
3 years ago
Read 2 more answers
Which rules define the function whose graph is shown?   on  x < −2   on  −2 ≤ x < 0   on  0 ≤ x < 2   on  2 ≤ x
jeyben [28]

Answer:

-4, -x^2, x^2, 4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
2. Find the common difference and the recursive formula. a. 22, 19, 16, 13, …
Musya8 [376]

Answer:

The common difference d is d = -3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

Step-by-step explanation:

We need to find the common difference and the recursive formula.

a. 22, 19, 16, 13, …

First we will find common difference

The formula of arithmetic sequence is: a_n=a_1+(n-1)d

where a_n is nth term, a_1 is 1st term and d is the difference

Looking at the sequence we get: a_1=22, a_2=19

Using these values we can find d, the common difference

a_n=a_1+(n-1)d\\put\:n=2, a_2=19, a_1=22\\19=22+(2-1)d\\19=22+d\\d=19-22\\d=-3

So, the common difference d is d = -3

Now, we will find the recursive formula:

The recursive formula is of type: a_n=a_{n-1}+d

We have found common difference d = -3

So, the recursive formula will be:

a_n=a_{n-1}+d\\a_n=a_{n-1}+(-3)\\a_n=a_{n-1}-3

The recursive formula is: \mathbf{a_n=a_{n-1}-3}

6 0
3 years ago
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