Answer:
d
Explanation:
it's called the hydrocarbon
Missing question:
(a) 1s2 2s2 2p6 3s1
(b) 1s2 2s2 2p6 3s2
(c) 1s2 2s2 2p6 3s2 3p1
(d) 1s2 2s2 2p6 3s2 3p4
(e) 1s2 2s2 2p6 3s2 3p5
Answer is: a) 1s²2s²2p⁶3s¹ (sodium).
Sodium have the largest second ionization energy, because when he lost one electron(first ionization energy), he have stable electron configuration of noble gas neon (1s²2s²2p⁶), so sodium do not need to lost second electron, because he will have unstable electron configuration.
Mass of cisplatin can be made : 144.6 g
<h3>Further explanation</h3>
Given
Reaction(unbalanced)
K2PtCl4 (aq) + ___NH3 (aq) ___Pt(NH3)2Cl2 (s) + ___KCl (aq)
200 g of K2PtCl4
Required
mass of cisplatin Pt(NH3)2Cl2
Solution
Balanced equation
K₂PtCl₄ (aq) + 2NH₃ (aq) ⇒Pt(NH₃)₂Cl₂ (s) + 2KCl (aq)
mol of K₂PtCl₄(MW=2.39+195+4.35.5=415 g/mol) :
mol = mass : Mw
mol = 200 : 415
mol = 0.482
From equation, mol ratio K₂PtCl₄ : Pt(NH₃)₂Cl₂ = 1 : 1, so mol Pt(NH₃)₂Cl₂ = 0.482
Mass of cisplatin Pt(NH₃)₂Cl₂(MW=195+2.14+6.1+2.35.5=300 g/mol) :
mass = mol x MW
mass = 0.482 x 300
mass = 144.6 g
Answer:
Maybe I know too much chemistry but how the metals (and the non-metals) react depends on where they are in the Periodic Table. The metals in groups I and II over on the far left side are explosively reactive and loose electrons and form ionic bonds. Examples: Na+1 has lost 1 electron and Li+2 has lost 2 electrons. The metals in the higher groups are more confusing but most of them share outer shell electrons and form covalent bonds. Examples: Fe2O3 (rust) where Iron shares 2X3 electrons with Oxygen which shares 3X2 electrons. Confused enough? :-)
The answer you'll be expected to give depends on the subject of the chapter you're studying. If you're studying covalent bonds, then the answer will probably be "form covalent bonds". If you're studying ionic bonds, then the answer will be "lose electrons".
Explanation:
This may not be the answer... I'm sorry if it's not
