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Katen [24]
3 years ago
9

What can account for the increased potential energy when atoms are close together?

Chemistry
2 answers:
Lisa [10]3 years ago
8 0

Answer:

D. Proton to proton repulsion

Explanation:

irina [24]3 years ago
3 0

Answer:

The correct answer is D.

Explanation:

The increase in potential energy when atoms are closer and closer is due to the force of repulsion Proton by Proton. The potential energy that a molecule may have will be due to the forces of attraction and repulsion with other molecules in its environment. The greater the force of repulsion, the greater the potential energy between the atoms.

Have a nice day!

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These cooked noodles were separated from the water they were cooked in. By which physical property were they separated? A. size
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Answer:

B. Density

Explanation:

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3 years ago
1.How many moles of each element are in 0.0250 mol of K 2 Cr O 4? 2. How many moles of ammonium ions are in 4.50 mol of (N H 4 )
noname [10]

Answer:

1. 0.0500 moles K, 0.0250 moles Cr and 0.1000 moles O.

2. 9.00 moles ammonium ions are present.

Explanation:

1. In 1mol of K2CrO4 there are 2 moles of K, 1 mole of Cr and 4 moles of O.

The moles in 0.0250 moles K2CrO4 are:

0.0250mol * 2 = 0.0500 moles K

0.0250mol * 1 = 0.0250 moles Cr

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5 0
3 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
PSYCHO15rus [73]

Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

5 0
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