Answer:
Mass = 33.515 g
Explanation:
Given data:
Volume of ammonia = 45.0 L
Temperature = 57.0°C (57 +273 = 330 K)
Pressure = 900 mmHg
Mass of ammonia = ?
Solution:
Formula:
PV = nRT
We will use R = 62.364 (L * mmHg)/(mol * K) because pressure is given in mmHg.
900 mmHg × 45.0 L = n × 62.364L * mmHg/mol * K × 330 K
40500 mmHg.L = n × 20580.12L * mmHg/mol
n= 40500 mmHg.L/ 20580.12L * mmHg/mol
n = 1.9679 mol
Mass of ammonia:
Mass = number of moles × molar mass
Mass = 1.9679 mol × 17.031 g/mol
Mass = 33.515 g
When we multiply or divide the values the number of significant figures must be equal to the less number of significant figures in given value.
if it is already as low as it can go
Answer
pH=8.5414
Procedure
The Henderson–Hasselbalch equation relates the pH of a chemical solution of a weak acid to the numerical value of the acid dissociation constant, Kₐ. In this equation, [HA] and [A⁻] refer to the equilibrium concentrations of the conjugate acid-base pair used to create the buffer solution.
pH = pKa + log₁₀ ([A⁻] / [HA])
Where
pH = acidity of a buffer solution
pKa = negative logarithm of Ka
Ka =acid disassociation constant
[HA]= concentration of an acid
[A⁻]= concentration of conjugate base
First, calculate the pKa
pKa=-log₁₀(Ka)= 8.6383
Then use the equation to get the pH (in this case the acid is HBrO)
Answer : The volume of hydrogen gas at STP is 4550 L.
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of gas = 100.0 atm
= final pressure of gas at STP = 1 atm
= initial volume of gas = 50.0 L
= final volume of gas at STP = ?
= initial temperature of gas = 
= final temperature of gas at STP = 
Now put all the given values in the above equation, we get:


Therefore, the volume of hydrogen gas at STP is 4550 L.