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Finding percent composition is fairly easy. You only need to divide the mass of an element by the total mass of the compound. We can do this one element at a time.
First, let's find the total mass by using the masses of the elements given on the periodic table.
7 x 12.011 (mass of Carbon) = 84.077
5 x 1.008 (mass of Hydrogen) = 5.04
3 x 14.007 (mass of Nitrogen) = 42.021
6 x 15.999 (mass of Oxygen) = 95.994
Add all of those pieces together.
84.077 + 5.04 + 42.021 + 95.994 = 227.132 g/mol is your total. Since we also just found the mass of each individual element, the next step will be very easy.
Carbon: 84.077 / 227.132 = 0.37016 ≈ 37.01 %
Hydrogen: 5.04 / 227.132 = 0.022189 ≈ 2.22 %
Nitrogen: 42.021 / 227.132 = 0.185 ≈ 18.5 %
Oxygen: 95.994 / 227.132 = 0.42263 ≈ 42.26 %
You can check your work by making sure they add up to 100%. The ones I just found add up to 99.99, which is close enough. A small difference (no more than 0.03 in my experience) is just a matter of where you rounded your numbers.
The mass change, or the mass defect, can be calculated by the formula that is very known to be associated with Albert Einstein.
E = Δmc²
where
E is the energy gained or released during the reaction
c is the speed of light equal to 3×10⁸ m/s
Δm is the mass change
(1.715×10³ kJ)(1,000 J/1 kJ) = Δm(3×10⁸ m/s)²
Δm = 1.91×10⁻¹¹ kg
Answer:
The original concentration of the acid was 0.605 M
Explanation:
Step 1: Data given
Volume of gas = 177.6 mL = 0.1176 L
Temperature = 25.8 °C = 298.95 K
Pressure = 799.7 torr = 799.7/ 760 = 1.0522368 atm
Volume of acid needed to react = 12.6 mL = 0.0126 L
Step 2: Calculate moles
p*V = n*R*T
n = (p*V)/(R*T)
⇒with n = the number of moles = TO BE DETERMINED
⇒with p = the pressure of the gas = 799.7 torr = 1.0522368 atm
⇒with V = the volume of the gas = 177.6 mL = 0.1776 L
⇒with R = the gas constant = 0.08206 L*atm/mol*K
⇒with T = the temperature = 25.8 °C = 298.95 K
n = 0.007618 moles
Step 3: Calculate original concentration
We need 0.007618 moles of acid to react with the same amount of moles gas
Concentration acid = moles / volume
Concentration acid = 0.007618 moles / 0.0126 L
Concentration acid = 0.605 M
The original concentration of the acid was 0.605 M
Answer: option D. triple bond and one lone pair
Explanation:
